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Question Number 98776 by  M±th+et+s last updated on 16/Jun/20

∫_0 ^∞ (((x−1))/(ln(F(x)(√5)+cos(πx)(ϕ)^(−x) −1)(√(F(x)(√5)+cos(πx)(ϕ)^(−x) −1))))dx    F(x)=Fib(x)=xth Extended fibonacci number  f:R→R  ϕ=((1+(√5))/2)

0(x1)ln(F(x)5+cos(πx)(φ)x1)F(x)5+cos(πx)(φ)x1dxF(x)=Fib(x)=xthExtendedfibonaccinumberf:RRφ=1+52

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