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Question Number 98776 by M±th+et+s last updated on 16/Jun/20
∫0∞(x−1)ln(F(x)5+cos(πx)(φ)−x−1)F(x)5+cos(πx)(φ)−x−1dxF(x)=Fib(x)=xthExtendedfibonaccinumberf:R→Rφ=1+52
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