All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 98821 by bramlex last updated on 16/Jun/20
∫∞0dxa2+x2=?
Answered by Ar Brandon last updated on 16/Jun/20
I=1a[arctan(xa)]0∞=1a[π2−0]{sincetan[π2]=+∞}⇒∫∞0dxa2+x2=π2a
Commented by bramlex last updated on 16/Jun/20
thanks
Terms of Service
Privacy Policy
Contact: info@tinkutara.com