Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 98885 by  M±th+et+s last updated on 16/Jun/20

find the range    f(x)=log_4 log_2 log_(1/2) (x)

findtherangef(x)=log4log2log12(x)

Commented by MJS last updated on 17/Jun/20

f(x) defined for 0<x<(1/2) ⇒ −∞<f(x)<+∞  log_(1/2)  x =−log_2  x  ⇒ x>0  log_2  (−log_2  x)  ⇒ −log_2  x >0 ⇒ 0<x<1  log_4  log_2  (−log_2  x)  ⇒ log_2  (−log_2  x) >0 ⇒ 0<x<(1/2)

f(x)definedfor0<x<12<f(x)<+log1/2x=log2xx>0log2(log2x)log2x>00<x<1log4log2(log2x)log2(log2x)>00<x<12

Commented by  M±th+et+s last updated on 17/Jun/20

thank you sir

thankyousir

Terms of Service

Privacy Policy

Contact: info@tinkutara.com