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Question Number 98919 by M±th+et+s last updated on 17/Jun/20

Commented by M±th+et+s last updated on 17/Jun/20

$l e t △ A B C i s a n e q u i l a t e r a l t r i a n g l e$ $t h e n f i n d$ $i . a r g (\frac{Z_{2} - Z_{3}}{Z_{3} - Z_{1}})$ $i i . c o m p l e x n u m b e r c o r r e s p o n d i n g t o$ $c i r c u m c e n t e r i n t e r m s o f Z_{1} & Z_{2} .$
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