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Question Number 98968 by Brokris last updated on 17/Jun/20

if x^x^x^x^(2020)    = 2020.  Solve for x

ifxxxx2020=2020.Solveforx

Commented by mr W last updated on 17/Jun/20

x^x^(...x^(2020) )  =2020  has the same root as  x^(2020) =2020  x=±((2020))^(1/(2020)) ≈±1.00377

xx...x2020=2020hasthesamerootasx2020=2020x=±20202020±1.00377

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