Question Number 98968 by Brokris last updated on 17/Jun/20
$$\mathrm{if}\:\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{\mathrm{x}^{\mathrm{2020}} } } } =\:\mathrm{2020}.\:\:\mathrm{Solve}\:\mathrm{for}\:\mathrm{x} \\ $$$$ \\ $$
Commented by mr W last updated on 17/Jun/20
$${x}^{{x}^{...{x}^{\mathrm{2020}} } } =\mathrm{2020} \\ $$$${has}\:{the}\:{same}\:{root}\:{as} \\ $$$${x}^{\mathrm{2020}} =\mathrm{2020} \\ $$$${x}=\pm\sqrt[{\mathrm{2020}}]{\mathrm{2020}}\approx\pm\mathrm{1}.\mathrm{00377} \\ $$