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Question Number 99007 by Rio Michael last updated on 18/Jun/20

$$\mathrm{Let}{I}_y=\underset{-2}{\stackrel{2}{\int }}[y^3\cos \left(\frac{y}{2}\right)+\frac{1}{2}]\left(\sqrt{4-y^2}\right)dy$$$$\mathrm{then}{I}_y=???$$

Answered by maths mind last updated on 18/Jun/20

$$try{\int }_{-2}^0+{\int }_0^2$$$$andputt=-xinfirstone$$$$f\left(x\right)=(x^{3}cos\left(\frac{x}{2}\right)+\frac{1}{2})\sqrt{4-x^2}weget$$$${\int }_0^2(f\left(x\right)+f(-x))dx$$

Commented by Rio Michael last updated on 18/Jun/20

$$\mathrm{Thanks},\mathrm{i}\mathrm{solved}\mathrm{it}\mathrm{already}.$$

Commented by maths mind last updated on 18/Jun/20

$$withepleaserNicesir$$

Answered by frc2crc last updated on 18/Jun/20

$$itshouldbe\pi$$

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