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Question Number 99025 by joki last updated on 18/Jun/20

Commented by bobhans last updated on 18/Jun/20

set 2207−(1/(2207−(1/(2207−(1/(2207−...)))))) = q  2207−(1/q) = q ⇒q^2 −2207q+1=0  q= ((2207 ± (√(4870845)))/2) = ((2207 ± 2207)/2)  case(1) q = 2207 ⇒((2207−(1/(2207−(1/(2207−...))))))^(1/(8  )) = ((2207))^(1/(8   ))  ≈ 2.618034056

set2207122071220712207...=q22071q=qq22207q+1=0q=2207±48708452=2207±22072case(1)q=220722071220712207...8=220782.618034056

Commented by joki last updated on 18/Jun/20

thanks sir

thankssir

Commented by MJS last updated on 18/Jun/20

(√(4870845))≠2207 ⇒ answer is only an approximation

48708452207answerisonlyanapproximation

Commented by bobhans last updated on 18/Jun/20

yes sir. my answer is approximation

yessir.myanswerisapproximation

Answered by bemath last updated on 18/Jun/20

let ((2207−(1/(2207−(1/(2207))−...))))^(1/(8  ))  = w  w^8  = 2207−(1/w^8 ) ⇒ w^(16)  −2207w^8  + 1=0

let22071220712207...8=ww8=22071w8w162207w8+1=0

Commented by mr W last updated on 18/Jun/20

wrong sir!  should be  w^8  = 2207−(1/w^8 )

wrongsir!shouldbew8=22071w8

Commented by joki last updated on 18/Jun/20

have done?what is the value w?

havedone?whatisthevaluew?

Commented by Rasheed.Sindhi last updated on 18/Jun/20

Sir bemath     I′ve tried to solve your q#98806  Please say something whether  it′s right or wrong.

SirbemathYou can't use 'macro parameter character #' in math modePleasesaysomethingwhetheritsrightorwrong.

Commented by bemath last updated on 18/Jun/20

sorry sir. i forgot. yes sir your answer   is correct

sorrysir.iforgot.yessiryouransweriscorrect

Commented by Rasheed.Sindhi last updated on 18/Jun/20

Thanx sir!

Thanxsir!

Answered by MJS last updated on 18/Jun/20

x=2207−(1/x)  x^2 −2207x+1=0  x=((2207±987(√5))/2); x≈2207 ⇒ x=((2207+987(√5))/2)  (x)^(1/8) =(√(√(√x)))  (√((2207+987(√5))/2))=((47+21(√5))/2)  (√((47+21(√5))/2))=((7+3(√5))/2)  (√((7+3(√5))/2))=((3+(√5))/2)

x=22071xx22207x+1=0x=2207±98752;x2207x=2207+98752x8=x2207+98752=47+215247+2152=7+3527+352=3+52

Commented by mr W last updated on 18/Jun/20

x=((2207−987(√5))/2) is also solution?

x=220798752isalsosolution?

Commented by MJS last updated on 18/Jun/20

solution of the polynome, yes. but  ((2207−987(√5))/2)≠2207−(1/(2207−(1/(2207...))))

solutionofthepolynome,yes.but22079875222071220712207...

Commented by bobhans last updated on 18/Jun/20

great sir...

greatsir...

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