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Question Number 99133 by mathocean1 last updated on 18/Jun/20

Equilibrate it using oxydation′s  number  (NH_4 )_2 Cr_2 O_7 →N_2 +H_2 O+Cr_(2  ) O_7

$${Equilibrate}\:{it}\:{using}\:{oxydation}'{s} \\ $$$${number} \\ $$$$\left({NH}_{\mathrm{4}} \right)_{\mathrm{2}} {Cr}_{\mathrm{2}} {O}_{\mathrm{7}} \rightarrow{N}_{\mathrm{2}} +{H}_{\mathrm{2}} {O}+{Cr}_{\mathrm{2}\:\:} {O}_{\mathrm{7}} \\ $$

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