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Question Number 99138 by babar last updated on 18/Jun/20

$$\mathrm{If}A\mathrm{and}B\mathrm{are}\mathrm{independent}\mathrm{events}\mathrm{and}$$$$P\left(C\right)=0,\mathrm{then}$$

Answered by Rio Michael last updated on 19/Jun/20

$$\mathrm{for}\mathrm{independent}\mathrm{events},P(A\cap B)=P\left(A\right)\times P\left(B\right)$$$$\mathrm{but}P\left(C{}^{\prime }\right)=0\Rightarrow P\left(C\right)=1.$$$$\Rightarrow C\mathrm{is}\mathrm{a}\mathrm{disjoined}\mathrm{event}$$

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