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Question Number 99139 by babar last updated on 18/Jun/20

$$\mathrm{One}\mathrm{ticket}\mathrm{is}\mathrm{selected}\mathrm{at}\mathrm{random}\mathrm{from}$$$$100\mathrm{tickets}\mathrm{numbered}00,01,02,...,99$$$$\mathrm{Suppose}A\mathrm{and}B\mathrm{are}\mathrm{the}\mathrm{sum}\mathrm{and}$$$$\mathrm{product}\mathrm{of}\mathrm{the}\mathrm{digit}\mathrm{found}\mathrm{on}\mathrm{the}\mathrm{ticket}.$$$$\mathrm{Then}P(A=7/B=0)\mathrm{is}\mathrm{given}\mathrm{by}$$

Answered by 1549442205 last updated on 19/Jun/20

$$$$$$07,70\mathrm{are}\mathrm{two}\mathrm{possibilities}\mathrm{to}\mathrm{success},\mathrm{the}$$$$\mathrm{partern}\mathrm{space}\mathrm{is}100.\mathrm{Hence},\mathrm{P}(\mathrm{A}=7,\mathrm{B}=0)=\frac{2}{100}=\frac{1}{50}$$

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