Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 9914 by Tawakalitu ayo mi last updated on 15/Jan/17

Answered by mrW1 last updated on 15/Jan/17

((QA)/(PQ))=((RA)/(PR))  ((QA)/(15))=((RA)/9)  QA=((15)/9)RA=(5/3)RA=(5/3)(QR−QA)  3QA=5QR−5QA  QA=(5/8)QR=(5/8)×16=10 cm  QM=(1/2)QR=(1/2)×16=8 cm  AM=QA−QM=10−8=2 cm

$$\frac{{QA}}{{PQ}}=\frac{{RA}}{{PR}} \\ $$$$\frac{{QA}}{\mathrm{15}}=\frac{{RA}}{\mathrm{9}} \\ $$$${QA}=\frac{\mathrm{15}}{\mathrm{9}}{RA}=\frac{\mathrm{5}}{\mathrm{3}}{RA}=\frac{\mathrm{5}}{\mathrm{3}}\left({QR}−{QA}\right) \\ $$$$\mathrm{3}{QA}=\mathrm{5}{QR}−\mathrm{5}{QA} \\ $$$${QA}=\frac{\mathrm{5}}{\mathrm{8}}{QR}=\frac{\mathrm{5}}{\mathrm{8}}×\mathrm{16}=\mathrm{10}\:{cm} \\ $$$${QM}=\frac{\mathrm{1}}{\mathrm{2}}{QR}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{16}=\mathrm{8}\:{cm} \\ $$$${AM}={QA}−{QM}=\mathrm{10}−\mathrm{8}=\mathrm{2}\:{cm} \\ $$

Commented by Tawakalitu ayo mi last updated on 15/Jan/17

God bless you sir. i really appreciate.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com