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Question Number 99244 by Ar Brandon last updated on 19/Jun/20

$$\underset{\mathrm{x}\to 0}{\lim }\frac{\sqrt{\mathrm{x}-4}-2}{2\mathrm{x}}=?$$

Answered by mahdi last updated on 19/Jun/20

$$\underset{x\to 0}{\lim }\frac{\sqrt{\mathrm{x}+4}-2}{2\mathrm{x}}\times \frac{\sqrt{\mathrm{x}+4}+2}{\sqrt{\mathrm{x}-4}+2}=$$$$\underset{x\to 0}{\lim }\frac{\mathrm{x}+4-4}{2\mathrm{x}(\sqrt{\mathrm{x}+4}+2)}=\underset{x\to 0}{\lim }\frac{1}{2(\sqrt{\mathrm{x}+4}+2)}=$$$$\frac{1}{8}$$$$(\sqrt{\mathrm{x}-4}\mathrm{in}\mathrm{x}=0\Rightarrow \sqrt{-4}=\nexists )$$$$\mathrm{i}\mathrm{thinks}\mathrm{you}\mathrm{most}\mathrm{riwte}\sqrt{\mathrm{x}+4}$$

Commented by Aziztisffola last updated on 19/Jun/20

$$=\frac{1}{8}$$

Commented by Ar Brandon last updated on 19/Jun/20

If it was the case I wouldn't have had problems. I also felt it's been erred.��

Commented by mahdi last updated on 19/Jun/20

$$\mathrm{tanks}\mathrm{Aziztisffola}\mathrm{for}\mathrm{giude}:)$$

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