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Question Number 99358 by PengagumRahasiamu last updated on 20/Jun/20

$$15\mathrm{men}\mathrm{can}\mathrm{complete}\mathrm{a}\mathrm{work}\mathrm{in}10\mathrm{days},$$$$\mathrm{working}8\mathrm{hrs}.\mathrm{per}\mathrm{day}.\mathrm{How}\mathrm{many}$$$$\mathrm{persons}\mathrm{are}\mathrm{required}\mathrm{to}\mathrm{complete}$$$$\mathrm{double}\mathrm{the}\mathrm{work}\mathrm{in}25\mathrm{days},\mathrm{working}$$$$6\mathrm{hrs}.\mathrm{per}\mathrm{day}?$$

Commented by john santu last updated on 20/Jun/20

$$16\mathrm{persons}$$

Answered by john santu last updated on 20/Jun/20

$$\Rightarrow 15\times 8\times 10=1\mathrm{work}$$$$\Rightarrow \mathrm{t}\times 6\times 25=2\mathrm{work}$$$$\iff \left(15\times 8\times 10\right)\times 2=\mathrm{t}\times 6\times 25$$$$\mathrm{t}=\frac{150\times 16}{150}=16\mathrm{persons}$$

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