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Question Number 99366 by PengagumRahasiamu last updated on 20/Jun/20

Two buses start from a point such that one bus travelling at 80 km/h reaches its destination 2 hours before the other bus which travels at 60 km/h. However the distance travelled by the bus travelling at 60 km/h is 40 km more than that of the other bus. Find the distance travelled by the bus which is travelling at 80 km/h.

Twobusesstartfromapointsuchthatonebustravellingat80km/hreachesitsdestination2hoursbeforetheotherbuswhichtravelsat60km/h.Howeverthedistancetravelledbythebustravellingat60km/his40kmmorethanthatoftheotherbus.Findthedistancetravelledbythebuswhichistravellingat80km/h.

Answered by MWSuSon last updated on 20/Jun/20

Distance should be 320km.

Distanceshouldbe320km.

Answered by MWSuSon last updated on 20/Jun/20

let Bus A be the bus travelling at 80km/h, and Bus B be the bus tra− velling 60km/h. speed = ((distance)/(time)) Bus A⇒80km/h=(x/t), x is the dist− ance and t is time taken. Bus B⇒60km/h=((40km+x)/t) from Bus B, t=((40+x)/(60)), but Bus A t− ook 2hrs less to reach its destination ⇒ t−2=((x−80)/(60)) ⇒Bus A = 80=(x/((x−80)/(60)))=((60x)/(x−80)) 80x−6400=60x 20x=6400 x=((6400)/(20)) x=320km//

letBusAbethebustravellingat80km/h,andBusBbethebustra−velling60km/h.speed=distancetimeBusA⇒80km/h=xt,xisthedist−anceandtistimetaken.BusB⇒60km/h=40km+xtfromBusB,t=40+x60,butBusAt−ook2hrslesstoreachitsdestination⇒t−2=x−8060⇒BusA=80=xx−8060=60xx−8080x−6400=60x20x=6400x=640020x=320km//

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