Question and Answers Forum

All Questions      Topic List

Limits Questions

Previous in All Question      Next in All Question      

Previous in Limits      Next in Limits      

Question Number 99392 by AwaisAhmed last updated on 20/Jun/20

Commented by PRITHWISH SEN 2 last updated on 21/Jun/20

To be continuous 4b=−2⇒b= −(1/2)

$$\mathrm{To}\:\mathrm{be}\:\mathrm{continuous}\: \\ $$$$\mathrm{4b}=−\mathrm{2}\Rightarrow\boldsymbol{\mathrm{b}}=\:−\frac{\mathrm{1}}{\mathrm{2}}\: \\ $$

Answered by Rio Michael last updated on 20/Jun/20

if f(x) is continuous, then it is continuous at x = −2 ⇒ lim_(x→−2^− ) f(x) = lim_(x→−2^+ ) f(x) = f(2) lim_(x→−2^− ) x = −2 and also lim_(x→−2^+ ) bx^2 = 4b also f(−2) = 4b ⇒ −2 = 4b ⇔ b = −(1/2)

$$\mathrm{if}\:{f}\left({x}\right)\:\mathrm{is}\:\mathrm{continuous},\:\mathrm{then}\:\mathrm{it}\:\mathrm{is}\:\mathrm{continuous}\:\mathrm{at}\:{x}\:=\:−\mathrm{2} \\ $$$$\Rightarrow\:\underset{{x}\rightarrow−\mathrm{2}^{−} } {\mathrm{lim}}\:{f}\left({x}\right)\:=\:\underset{{x}\rightarrow−\mathrm{2}^{+} } {\mathrm{lim}}\:{f}\left({x}\right)\:=\:{f}\left(\mathrm{2}\right) \\ $$$$\underset{{x}\rightarrow−\mathrm{2}^{−} } {\mathrm{lim}}\:{x}\:=\:−\mathrm{2}\:\mathrm{and}\:\mathrm{also}\:\underset{{x}\rightarrow−\mathrm{2}^{+} } {\mathrm{lim}}\:{bx}^{\mathrm{2}} \:=\:\mathrm{4}{b}\:\:\mathrm{also}\:{f}\left(−\mathrm{2}\right)\:=\:\mathrm{4}{b} \\ $$$$\Rightarrow\:−\mathrm{2}\:=\:\mathrm{4}{b}\:\Leftrightarrow\:{b}\:=\:−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$ \\ $$

Commented by PRITHWISH SEN 2 last updated on 21/Jun/20

sorry itis a typo

$$\mathrm{sorry}\:\mathrm{itis}\:\mathrm{a}\:\mathrm{typo} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com