Question and Answers Forum

All Questions      Topic List

Limits Questions

Previous in All Question      Next in All Question      

Previous in Limits      Next in Limits      

Question Number 99392 by AwaisAhmed last updated on 20/Jun/20

Commented by PRITHWISH SEN 2 last updated on 21/Jun/20

$$\mathrm{To}\mathrm{be}\mathrm{continuous}$$$$4\mathrm{b}=-2\Rightarrow \mathbf{b}=-\frac{1}{2}$$

Answered by Rio Michael last updated on 20/Jun/20

$$\mathrm{if}f\left(x\right)\mathrm{is}\mathrm{continuous},\mathrm{then}\mathrm{it}\mathrm{is}\mathrm{continuous}\mathrm{at}x=-2$$$$\Rightarrow \underset{x\to -2^{-}}{\lim }f\left(x\right)=\underset{x\to -2^{+}}{\lim }f\left(x\right)=f\left(2\right)$$$$\underset{x\to -2^{-}}{\lim }x=-2\mathrm{and}\mathrm{also}\underset{x\to -2^{+}}{\lim }{bx}^2=4b\mathrm{also}f(-2)=4b$$$$\Rightarrow -2=4b\iff b=-\frac{1}{2}$$$$$$

Commented by PRITHWISH SEN 2 last updated on 21/Jun/20

$$\mathrm{sorry}\mathrm{itis}\mathrm{a}\mathrm{typo}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com