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Question Number 99513 by naka3546 last updated on 21/Jun/20

x,y,z  ∈  R^+   x^2  + y^3  + z^4   =  x^4  + y^5  + z^6   Prove  that       (x^2 /(y^4 +1))  +  (y^2 /(z^4 +1))  +  (z^2 /(x^4 +1))  ≥  ((x^2 +y^2 +z^2 )/2)

$${x},{y},{z}\:\:\in\:\:\mathbb{R}^{+} \\ $$$${x}^{\mathrm{2}} \:+\:{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{4}} \:\:=\:\:{x}^{\mathrm{4}} \:+\:{y}^{\mathrm{5}} \:+\:{z}^{\mathrm{6}} \\ $$$${Prove}\:\:{that} \\ $$$$\:\:\:\:\:\frac{{x}^{\mathrm{2}} }{{y}^{\mathrm{4}} +\mathrm{1}}\:\:+\:\:\frac{{y}^{\mathrm{2}} }{{z}^{\mathrm{4}} +\mathrm{1}}\:\:+\:\:\frac{{z}^{\mathrm{2}} }{{x}^{\mathrm{4}} +\mathrm{1}}\:\:\geqslant\:\:\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} }{\mathrm{2}} \\ $$

Commented by Rasheed.Sindhi last updated on 21/Jun/20

Mr naka I have tried to answer your q#95846,  please say whether the answer  is correct or incorrect.

$${Mr}\:{naka}\:{I}\:{have}\:{tried}\:{to}\:{answer}\:{your}\:{q}#\mathrm{95846}, \\ $$$${please}\:{say}\:{whether}\:{the}\:{answer} \\ $$$${is}\:{correct}\:{or}\:{incorrect}. \\ $$

Commented by naka3546 last updated on 22/Jun/20

I have  confirmed , sir.  That′s  correct.

$${I}\:{have}\:\:{confirmed}\:,\:{sir}.\:\:{That}'{s}\:\:{correct}. \\ $$

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