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Question Number 99529 by Dwaipayan Shikari last updated on 21/Jun/20

Answered by mr W last updated on 21/Jun/20

$$a=accelerationofm$$$$A=accelerationofM$$$$ma=-mg\frac{\mu }{2}$$$$\Rightarrow a=-\frac{\mu g}{2}$$$$MA=-(M+m)g\mu +mg\frac{\mu }{2}$$$$\Rightarrow A=-(1+\frac{m}{2M})g\mu$$$$\mathrm{\Delta }a=a-A=\frac{1}{2}(1+\frac{m}{M})\mu g$$$$t=\sqrt{\frac{2L}{\mathrm{\Delta }a}}$$$$\Rightarrow t=2\sqrt{\frac{L}{(1+\frac{m}{M})\mu g}}$$

Commented by Dwaipayan Shikari last updated on 21/Jun/20

You are right! sir.

Commented by Dwaipayan Shikari last updated on 21/Jun/20

I want to thank you for spending your valuable time

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