If α=((2π)/7) then what is the value of (sinαsin2αsin4α)


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Question Number 99620 by Dwaipayan Shikari last updated on 22/Jun/20

$I f α = \frac{2 π}{7} t h e n w h a t i s t h e v a l u e o f (s i n α s i n 2 α s i n 4 α)$
Commented by Dwaipayan Shikari last updated on 22/Jun/20

$I h a v e f o u n d a w a y t o s o l v e i t$ $S u p p o s e$ $c o s α + c o s 2 α + c o s 4 α = \frac{1}{2 s i n α} [s i n 2 α + s i n 3 α - s i n α + s i n 5 α - s i n 3 α]$ $= \frac{1}{2 s i n α} [s i n \frac{4 π}{7} + s i n \frac{10 π}{7} - s i n \frac{2 π}{7}]$ $= \frac{1}{2 s i n \frac{2 π}{7}} [- s i n \frac{2 π}{7}]$ $= - \frac{1}{2}$ $W e c a n a l s o f i n d (s i n α + s i n 2 α + s i n 4 α) = \frac{\sqrt{7}}{2}$ $S o (s i n α s i n 2 α s i n 4 α) = - \frac{1}{4} (s i n α + s i n 2 α + s i n 4 α) = - \frac{\sqrt{7}}{8}$ $P l e a s e c h e c k t h i s (S i r, m y p r o c e s s t a k e s a l o n g t i m e a n d s o l a r g e i n s i z e)$ $S o i {c a n}^{'} t i n c l u d e e v e r y d e t a i l e d p r o v e$
	Answered by MWSuSon last updated on 22/Jun/20

	$\sin (\frac{2 π}{7}) \sin (\frac{4 π}{7}) \sin (\frac{8 π}{7}) = - \frac{\sqrt{7}}{8}$
	Commented by Dwaipayan Shikari last updated on 22/Jun/20

	$C a n y o u d e s c r i b e i t s i r ?$
	Commented by MWSuSon last updated on 22/Jun/20
	sir, do you mean the trig identity I used?
	Commented by Dwaipayan Shikari last updated on 22/Jun/20
	Sir I am student .so I want to know the process for solving it
	Commented by MWSuSon last updated on 22/Jun/20
	okay sir, I am also a student, to save time I just plugged in the value of the angle into the expression, but you can make use of the factor formulae to solve it.
	Commented by john santu last updated on 22/Jun/20

	$wrong . it should be \frac{\sqrt{7}}{8}$
	Commented by john santu last updated on 22/Jun/20

	Commented by MWSuSon last updated on 22/Jun/20
	sir I think there should be a negative sign. please recheck.
	Commented by john santu last updated on 22/Jun/20

	$no . \sin \frac{π}{7} > 0$ $\sin \frac{4 π}{7} > 0$ $\sin \frac{8 π}{7} = \sin (π + \frac{π}{7}) = \sin \frac{π}{7} > 0$
	Commented by bemath last updated on 22/Jun/20

	Commented by bemath last updated on 22/Jun/20

	$positive answer$
	Commented by MWSuSon last updated on 22/Jun/20
	Oh I see, thanks for the correction.
	Commented by Dwaipayan Shikari last updated on 22/Jun/20

	$s i r i t w i l l b e - \frac{\sqrt{7}}{8}$
	Commented by Dwaipayan Shikari last updated on 22/Jun/20

	$S i r, s i n (π + \frac{π}{7}) = - s i n \frac{π}{7}$
	Commented by Dwaipayan Shikari last updated on 22/Jun/20

	$P l e a s e r e c h e c k$
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