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Question Number 99645 by bramlex last updated on 22/Jun/20
Ifx,y>0then∣xy−x+y2∣+∣x+y2+xy∣=
Commented bybemath last updated on 22/Jun/20
sincexy>0&x+y2>0 sox+y2+xy>0 case(1)ifxy−x+y2>0 thenxy−x+y2+x+y2+xy=2xy case(2)ifxy−x+y2<0 then−xy+x+y2+x+y2+xy=x+y
Answered by Farruxjano last updated on 22/Jun/20
Whenx,y>0⇒x+y2+xy>0⇒ ∣x+y2+xy∣=x+y2+xy WeknowinequalityKoshi: x+y2⩾xywhenx,y>0So, ∣xy−x+y2∣=x+y2−xy ∣xy−x+y2∣+∣x+y2+xy∣=x+y2−xy+ +x+y2+xy=x+y▴.
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