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Question Number 99905 by Rio Michael last updated on 23/Jun/20

Commented by Rio Michael last updated on 23/Jun/20

$P and Q are two identical straight cables each of electrical resistance 20.0 Ω .$ $placed 4.8 cm apart in air .$ $(a) find the current through each cable$ $(b) draw the magnetic field pattern in the region between P and Q$ $(c) determine the resultant magnetic flux density at the point R due to$ $P and Q only .$
Commented by smridha last updated on 24/Jun/20

$c u r r e n t t h r o u g h e a c h c a b l e s$ $I = \frac{12}{20} = 0.6 A (p a r a l l e l c o m b i n a t i o n)$ $t h e d i r e c r i o n o f c u r r e n t f l o w$ $t h r o u g h t h e e a c h c o n d u c t o r (p a n d q)$ $i s s a m e s o t h e r e s u l t a n t m a n g n e t i c$ $f l u x d e n s i t y i s a t R i s$ $B = [\frac{μ_{0} I}{2 π (1.8 \times 10^{- 2})} + \frac{μ_{0} I}{2 π (3 \times 10^{- 2})}] T$ $= \frac{4 π \times 10^{- 7} \times 0.6 \times 4.8 \times 10^{- 2}}{2 π \times 5.4 \times 10^{- 4}}$ $= 1.0666 \times 10^{- 5} T$
Commented by Rio Michael last updated on 24/Jun/20

$Brilliant sir . . thank you . sir if$ $i^{'} m to draw the magnetic pattern$ $will it be like this ?$ $↺ ↺$
Commented by smridha last updated on 24/Jun/20

$y e a h o f c o u r s e j u s t s i m p l e$ $a s {A m p e a r}^{'} s c i r c u i t a l L a w . . . t a k e$ $a c l o s e d l o o p a r o u n d t h e w i r e$ $a n d a p p l y t h e r i g h t h a n d t h u m b$ $r u l e . . {t h a t}^{'} s e a s y f o r y o u . .$
Commented by Rio Michael last updated on 24/Jun/20

$thanks sir for the explanations$
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