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Question Number 99972 by bobhans last updated on 24/Jun/20

Commented by bemath last updated on 24/Jun/20

$$\mathrm{b}=9\Rightarrow \underset{x\to 0}{\lim }\frac{\mathrm{a}}{2\sqrt{\mathrm{ax}+9}}=\frac{1}{3};\frac{\mathrm{a}}{6}=\frac{1}{3}$$$$\mathrm{a}=2.\Rightarrow \underset{x\to 1}{\lim }\frac{\sqrt{9\mathrm{x}-4}-\sqrt{5}}{\mathrm{x}-1}=\frac{9}{2\sqrt{5}}$$$$$$

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