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Question Number 99982 by Dwaipayan Shikari last updated on 24/Jun/20
Commented by mr W last updated on 24/Jun/20
a=gμ=gtanθ⇒θ=tan−11μ=π2−tan−1μ
Commented by Dwaipayan Shikari last updated on 24/Jun/20
f=μmaf=mgag=tanθ,a=gμ,tanθ=1μθ=tan−11μθ=tan−1(2)
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