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Question Number 99982 by Dwaipayan Shikari last updated on 24/Jun/20

Commented by mr W last updated on 24/Jun/20

$$a=\frac{g}{\mu }=g\tan \theta$$$$\Rightarrow \theta ={\tan }^{-1}\frac{1}{\mu }=\frac{\pi }{2}-{\tan }^{-1}\mu$$

Commented by Dwaipayan Shikari last updated on 24/Jun/20

$$f=\mu ma$$$$f=mg$$$$\frac{a}{g}=tan\theta ,a=\frac{g}{\mu },tan\theta =\frac{1}{\mu }\theta ={\tan }^{-1}\frac{1}{\mu }\theta ={\tan }^{-1}\left(2\right)$$$$$$$$$$

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