A 50 g lead bullet, sp. heat 0.02 is initially at 30°C. It is fired vertically upwards with a speed of 840 m/s and on returning to the starting level strikes a cake of ice at 0°C. How much ice is melted? Assume that all energy is spent in melting only (L = 80 cal/g).


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Question Number 23361 by Tinkutara last updated on 29/Oct/17

$A 50 g lead bullet, sp . heat 0.02 is$ $initially at 30 ° C . It is fired vertically$ $upwards with a speed of 840 m / s and$ $on returning to the starting level strikes$ $a cake of ice at 0 ° C . How much ice is$ $melted ? Assume that all energy is$ $spent in melting only (L = 80 cal / g) .$
	Answered by ajfour last updated on 29/Oct/17

	$(I a s s u m e s p e c i f i c h e a t = \frac{0.02 c a l}{g C °})$ $m L + M c △ T + △ K = 0$ $m (80 \times 4.182) + 50 \times 0.02 \times 4.2 \times 30$ $- \frac{1}{2} \times \frac{50}{1000} \times {(840)}^{2} = 0$ $\approx \Rightarrow m (42 \times 8) = 3 \times 42 + 42 \times 420$ $o r m = \frac{423}{8} g \approx 53 g .$
	Commented by Tinkutara last updated on 29/Oct/17

	$Thank you very much Sir!$
	Commented by ajfour last updated on 29/Oct/17

	$m : m a s s o f i c e m e l t e d$ $L : L a t e n t h e a t o f i c e$ $M : m a s s o f b u l l e t$
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