A bullet of mass 180g is fired horizontally into a fixed wooden block with a speed of 24m/s. if the bullet is brought to rest in 0.4sec by a constant resistance, calculate the distance moved by the bullet in the wood


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Question Number 197155 by otchereabdullai@gmail.com last updated on 09/Sep/23

$A b u l l e t o f m a s s 180 g i s f i r e d$ $h o r i z o n t a l l y i n t o a f i x e d w o o d e n$ $b l o c k w i t h a s p e e d o f 24 m / s . i f t h e$ $b u l l e t i s b r o u g h t t o r e s t i n 0.4 s e c b y a$ $c o n s t a n t r e s i s t a n c e, c a l c u l a t e t h e$ $d i s t a n c e m o v e d b y t h e b u l l e t i n t h e$ $w o o d$
	Answered by deleteduser1 last updated on 09/Sep/23

	$v^{2} = u^{2} + 2 a s \Rightarrow - 24^{2} = 2 a s$ $s = u t + \frac{1}{2} {a t}^{2} \Rightarrow s = 9.6 + \frac{a {(0.4)}^{2}}{2} = 9.6 + 0.08 a$ $\Rightarrow \frac{- 576}{2 a} = 9.6 + 0.08 a \Rightarrow 0.16 a^{2} + 19.2 a + 576 = 0$ $\Rightarrow a = - 60 {m s}^{- 2} \Rightarrow s = 9.6 - 4.8 = 4.8 m$
	Commented by otchereabdullai@gmail.com last updated on 09/Sep/23

	$t h a n k s s i r$
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