A function f is given by f(x) = { ((x^2 −3, 0≤x<2)),((4x−7, 2≤x<4)) :} is such that f(x) = f(x + 4) find f(27) and f(−106).


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Question Number 75083 by Rio Michael last updated on 07/Dec/19
$A function f is given by f(x) = { ((x^2 −3, 0≤x<2)),((4x−7, 2≤x<4)) :} is such that f(x) = f(x + 4) find f(27) and f(−106).$
$A f u n c t i o n f i s g i v e n b y$ $f (x) = {\begin{cases} x^{2} - 3, 0 ⩽ x < 2 \\ 4 x - 7, 2 ⩽ x < 4 \end{cases}$ $i s s u c h t h a t f (x) = f (x + 4)$ $f i n d f (27) a n d f (- 106) .$
	Answered by MJS last updated on 07/Dec/19

	$27 = 6 \times 4 + 3$ $- 106 = - 27 \times 4 + 2$ $\Rightarrow$ $f (27) = f (3) = 5$ $f (- 106) = f (2) = 1$
	Commented by Rio Michael last updated on 07/Dec/19

	$t h a n k y o u s i r, i g o t t h e n o w$
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