A pair of oppositely charged plane parallel plates each of area,100cm^2 has the electric field of the value 5.0×10^4 N/C.Calculate the charge on each plate.


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Question Number 40773 by Necxx last updated on 27/Jul/18

$A p a i r o f o p p o s i t e l y c h a r g e d p l a n e$ $p a r a l l e l p l a t e s e a c h o f a r e a, 100 {c m}^{2}$ $h a s t h e e l e c t r i c f i e l d o f t h e v a l u e$ $5.0 \times 10^{4} N / C . C a l c u l a t e t h e c h a r g e$ $o n e a c h p l a t e .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18

	$E = \frac{σ}{ϵ_{0}} s o σ = E ϵ_{0}$ $q = σ A = E ϵ_{0} A$ $q = 5.0 \times 10^{4} \times 8.854 \times 10^{- 12} \times 100 \times 10^{- 4}$ $= 5.0 \times 8.854 \times 10^{4 - 12 + 2 - 4}$ $= 44.27 \times 10^{- 10} C$
	Commented by Necxx last updated on 27/Jul/18

	$w o w . T h a n k s s o m u c h$
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