A parallel plate capacitor of plate spacing, 1mm is charged to a potential of 50V.Find the energy density in the capacitor


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Question Number 40786 by Necxx last updated on 27/Jul/18

$A p a r a l l e l p l a t e c a p a c i t o r o f p l a t e$ $s p a c i n g, 1 m m i s c h a r g e d t o a p o t e n t i a l$ $o f 50 V . F i n d t h e e n e r g y d e n s i t y i n$ $t h e c a p a c i t o r$
	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18

	$e n e r g y = \frac{1}{2} C V^{2}$ $e n e r g y d e n s i t y = \frac{\frac{1}{2} C V^{2}}{A d} C = c a p s c i t a n c e$ $V = p o t e n t i a l d i f f e r e n c e$ $A = a r e a o f p l a t e o f c s p a c i t o r$ $d = s e p a r a t i o n b e t w e e n p l a t e$ $C = \frac{ϵ_{0} A}{d}$ $e n e r g y d e n s i t y = \frac{1}{2} \times \frac{\frac{ϵ_{0} A}{d} . V^{2}}{A d}$ $= \frac{1}{2} . ϵ_{0} . \frac{V^{2}}{d^{2}}$
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