A particle is projected at an angle 60° with speed 10(√3) m/s from the point A as shown in the figure. At the same time the wedge is made to move with speed 10(√3) m/s toward right as shown in figure. Find the time after which particle will strike the wedge.


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Question Number 18265 by Tinkutara last updated on 17/Jul/17

$A particle is projected at an angle 60 °$ $with speed 10 \sqrt{3} m / s from the point A$ $as shown in the figure . At the same$ $time the wedge is made to move with$ $speed 10 \sqrt{3} m / s toward right as shown$ $in figure . Find the time after which$ $particle will strike the wedge .$
Commented by Tinkutara last updated on 17/Jul/17

Commented by ajfour last updated on 18/Jul/17

$In order to collide at time t$ $10 \sqrt{3} t = ycot 30 ° + (10 \sqrt{3}) [\cos 60 °] t$ $10 \sqrt{3} t = y \sqrt{3} + 5 \sqrt{3} t$ $y = 5 t$ $Also y = (10 \sqrt{3}) (\frac{\sqrt{3}}{2}) t - \frac{{gt}^{2}}{2}$ $\Rightarrow 5 t = 15 t - {5 t}^{2}$ $t^{2} - 2 t = 0$ $t = 2 s .$
Commented by ajfour last updated on 18/Jul/17

$and just now .$
Commented by Tinkutara last updated on 18/Jul/17

$Thanks Sir!$
Commented by Tinkutara last updated on 07/Mar/18
Sir I have a doubt now. Sorry for too late! But why ycot30° is used?
Commented by ajfour last updated on 08/Mar/18

$t h e w e d g e h a s t o t r a v e l t h i s e x t r a$ $h o r i z o n t a l d i s t a n c e t o c o l l i d e w i t h$ $t h e p a r t i c l e i f t h e y c o l l i d e a t l e v e l$ $y = y .$
Commented by Tinkutara last updated on 08/Mar/18
Oh yes thanks! ☺��
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