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Question Number 7489 by Obenfo last updated on 31/Aug/16

$$\mathrm{A}\mathrm{pen}\mathrm{with}\mathrm{a}\mathrm{cylindrical}\mathrm{barrel}\mathrm{of}$$$$\mathrm{diameter}2\mathrm{cm}\mathrm{and}\mathrm{height}10.5\mathrm{cm},$$$$\mathrm{filled}\mathrm{with}\mathrm{ink},\mathrm{can}\mathrm{write}3300\mathrm{words}.$$$$\mathrm{How}\mathrm{many}\mathrm{words}\mathrm{can}\mathrm{be}\mathrm{written}\mathrm{with}$$$$\mathrm{that}\mathrm{pen}\mathrm{using}100\mathrm{ml}\mathrm{of}\mathrm{ink}.$$$$(\mathrm{Take}1\mathrm{cc}=1\mathrm{ml})$$

Answered by sandy_suhendra last updated on 31/Aug/16

$$thevolumeofcylindrical=\pi r^{2}h=\frac{22}{7}\times 1^2\times 10.5=33cc$$$$100ccinkcanwrite=\frac{100}{33}\times 3,300words=10,000words$$

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