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Question Number 66746 by John Kaloki Musau last updated on 20/Aug/19

A point T  divides a line AB internally in the ratio 5:2. Given that A is (-4,10) and B is (10,3), find the coordinates of T.

ApointTdividesalineABinternallyintheratio5:2.GiventhatAis(4,10)andBis(10,3),findthecoordinatesofT.

Answered by mr W last updated on 19/Aug/19

x_T =x_A +(5/7)(x_B −x_A )=−4+(5/7)(10+4)=6  y_T =y_A +(5/7)(y_B −y_A )=10+(5/7)(3−10)=5  ⇒T(6,5)

xT=xA+57(xBxA)=4+57(10+4)=6yT=yA+57(yByA)=10+57(310)=5T(6,5)

Commented by John Kaloki Musau last updated on 19/Aug/19

correct

Answered by Rio Michael last updated on 19/Aug/19

 T(x,y) =( ((μx_1  + λx_2 )/(μ + λ)), ((μy_1  + λy_2 )/(μ + λ)))........internal division  T(x,y) = (((5(−4) + 2(10))/(5+2)) , ((5(10) + 2(3))/(5 + 2)))  T(x,y) = (0, ((56)/7))

T(x,y)=(μx1+λx2μ+λ,μy1+λy2μ+λ)........internaldivisionT(x,y)=(5(4)+2(10)5+2,5(10)+2(3)5+2)T(x,y)=(0,567)

Commented by mr W last updated on 20/Aug/19

please check sir:  it should be  T(x,y) = (((2(−4) + 5(10))/(5+2)) , ((2(10) + 5(3))/(5 + 2)))  T(x,y) = (6, 5)

pleasechecksir:itshouldbeT(x,y)=(2(4)+5(10)5+2,2(10)+5(3)5+2)T(x,y)=(6,5)

Commented by mr W last updated on 20/Aug/19

 T(x,y) =( ((μx_2  + λx_1 )/(μ + λ)), ((μy_2  + λy_1 )/(μ + λ)))........internal division

T(x,y)=(μx2+λx1μ+λ,μy2+λy1μ+λ)........internaldivision

Commented by Rio Michael last updated on 21/Aug/19

your right sir thanks

yourrightsirthanks

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