A real image 3 times the size of the object formed by a concave mirror on a screen. later both the object & the screen are shifted untill the image formed is 6 times the size of the object. if the distnce moved is 15cm. calculate the focal length of the mirror.


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*Question Number 22657 by D¬ B£$T* last updated on 21/Oct/17**

$A r e a l i m a g e 3 t i m e s t h e s i z e o f t h e$ $o b j e c t f o r m e d b y a c o n c a v e m i r r o r$ $o n a s c r e e n . l a t e r b o t h t h e o b j e c t$ $& t h e s c r e e n a r e s h i f t e d u n t i l l t h e$ $i m a g e f o r m e d i s 6 t i m e s t h e s i z e$ $o f t h e o b j e c t . i f t h e d i s t n c e m o v e d$ $i s 15 c m . c a l c u l a t e t h e f o c a l l e n g t h$ $o f t h e m i r r o r .$
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