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Question Number 210912 by Tawa11 last updated on 21/Aug/24

A uniform stick AB of length L and mass M is balanced horizontally on a knife edge 10.0cm from A when an object of mass 400g is suspended at A. When the knife edge is moved 5cm further, the object has to be moved to a point 9.00cm from A for the stick to balance. Represent the balance system with a suitable diagram, determine the mass and Length of the stick

Answered by Tawa11 last updated on 21/Aug/24

Answered by mr W last updated on 21/Aug/24

Commented by mr W last updated on 21/Aug/24

$$400\times 10=M\times (\frac{L}{2}-10)...\left(i\right)$$$$400\times (15-9)=M\times (\frac{L}{2}-15)...\left(ii\right)$$$$\left(i\right)/\left(ii\right):$$$$\frac{10}{6}=\frac{\frac{L}{2}-10}{\frac{L}{2}-15}$$$$\Rightarrow L=45cm$$$$400\times 10=M\times (\frac{45}{2}-10)$$$$\Rightarrow M=320g$$

Commented by Tawa11 last updated on 21/Aug/24

$$\mathrm{Thanks}\mathrm{sir}.\mathrm{I}\mathrm{really}\mathrm{appreciate}.$$$$\mathrm{I}\mathrm{understand}\mathrm{very}\mathrm{well}\mathrm{now}.$$

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