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AlgebraQuestion and Answers: Page 218

Question Number 126931 Answers: 1 Comments: 0

y=(1−x)^(cosx)

$y = {(1 - x)}^{c o s x}$

Question Number 126930 Answers: 1 Comments: 4

(√(1997×1996×1995×1994+1)) =?

$\sqrt{1997 \times 1996 \times 1995 \times 1994 + 1} = ?$

Question Number 126887 Answers: 2 Comments: 2

... calculus... please solve: ( with explanation) {_(x^2 +y=3) ^(x+y^2 =5)

$. . . c a l c u l u s . . .$ $p l e a s e s o l v e : (w i t h e x p l a n a t i o n)$ ${_{x^{2} + y = 3}^{x + y^{2} = 5}$

Question Number 126882 Answers: 1 Comments: 0

x^x =3

$x^{x} = 3$

Question Number 126845 Answers: 3 Comments: 0

... calculus (I)... prove :: i:: ⌊2x⌋=^? ⌊x⌋+⌊x+(1/2)⌋ ii:: ⌊3x⌋=⌊x⌋+⌊x+(1/3)⌋+⌊x+(2/3)⌋

$. . . c a l c u l u s (I) . . .$ $p r o v e ::$ $i :: ⌊ 2 x ⌋ \overset{?}{=} ⌊ x ⌋ + ⌊ x + \frac{1}{2} ⌋$ $i i :: ⌊ 3 x ⌋ = ⌊ x ⌋ + ⌊ x + \frac{1}{3} ⌋ + ⌊ x + \frac{2}{3} ⌋$

Question Number 126723 Answers: 0 Comments: 2

Question Number 126702 Answers: 1 Comments: 0

if tanh(x/2)=t prove that cosh(x)=((1+t^2 )/(1−t^2 ))

$i f t a n h \frac{x}{2} = t p r o v e t h a t c o s h (x) = \frac{1 + t^{2}}{1 - t^{2}}$

Question Number 126701 Answers: 2 Comments: 0

use right triangles to explain why cos^(−1) (x)+sin^(−1) (x)=π/2

$u s e r i g h t t r i a n g l e s t o e x p l a i n$ $w h y {c o s}^{- 1} (x) + {s i n}^{- 1} (x) = π / 2$

Question Number 126700 Answers: 2 Comments: 0

θ=sin^(−1) ((2/5)) find cos(θ) and tan(θ)

$θ = {s i n}^{- 1} (\frac{2}{5}) f i n d c o s (θ) a n d t a n (θ)$

Question Number 126619 Answers: 2 Comments: 0

5^x + 7^x = (9.8)^x x = ?

$5^{x} + 7^{x} = {(9.8)}^{x}$ $x = ?$

Question Number 126504 Answers: 0 Comments: 0

Question Number 126484 Answers: 0 Comments: 6

Question Number 126482 Answers: 1 Comments: 0

Question Number 126430 Answers: 3 Comments: 1

log _6^(15) =a log _(12)^(18) =b find log _(25)^(24) in terms of a and b

$\log_{6}^{15} = a \log_{12}^{18} = b find \log_{25}^{24}$ $in terms of a and b$

Question Number 126391 Answers: 3 Comments: 0

show that m^2 +m and 2m+1 are prime betwen them.

$s h o w t h a t$ $m^{2} + m a n d 2 m + 1 a r e p r i m e b e t w e n$ $t h e m .$

Question Number 126363 Answers: 2 Comments: 0

x^3 −x−c=0 ; [c<2/(3(√3))] (Solve by a method other than trigonometric solution).

$x^{3} - x - c = 0; [c < 2 / (3 \sqrt{3})]$ $(S o l v e b y a m e t h o d o t h e r t h a n$ $t r i g o n o m e t r i c s o l u t i o n) .$

Question Number 126329 Answers: 1 Comments: 0

Question Number 126180 Answers: 2 Comments: 0

solve ∣ ∣x−1∣ −2∣ = ∣ x−3 ∣

$s o l v e ∣ ∣ x - 1 ∣ - 2 ∣ = ∣ x - 3 ∣$

Question Number 126165 Answers: 0 Comments: 1

if: b^2 = −3 −c^2 +2(a−b−c) −a^2 calculate: a + b + c = ?

$i f : b^{2} = - 3 - c^{2} + 2 (a - b - c) - a^{2}$ $c a l c u l a t e : a + b + c = ?$

Question Number 126161 Answers: 3 Comments: 0

find “a” ^a (√(a^2 )) = ((4^(−(1/2)) )^(1/2) )^(−2)

$f i n d ‘ ‘ a^{″}$ $^{a} \sqrt{a^{2}} = {({(4^{- \frac{1}{2}})}^{\frac{1}{2}})}^{- 2}$

Question Number 126109 Answers: 2 Comments: 0

....nice calculus... verify that :: A=(((2+(√5)))^(1/3) /(1+(√5))) is a rational number ...

$. . . . n i c e c a l c u l u s . . .$ $v e r i f y t h a t :: A = \frac{\sqrt[3]{2 + \sqrt{5}}}{1 + \sqrt{5}} i s$ $a r a t i o n a l n u m b e r . . .$

Question Number 126105 Answers: 1 Comments: 1

1≤a;b;c;d≤2 ∣(1−a)(1−b)(1−c)(1−d)∣≤((abcd)/4)

$1 ⩽ a; b; c; d ⩽ 2$ $∣ (1 - a) (1 - b) (1 - c) (1 - d) ∣⩽ \frac{a b c d}{4}$

Question Number 126104 Answers: 0 Comments: 1

((a+b)/c) + ((b+c)/a) +((a+c)/b) ≥ 4a−3b+c a≥b≥c

$\frac{a + b}{c} + \frac{b + c}{a} + \frac{a + c}{b} ⩾ 4 a - 3 b + c$ $a ⩾ b ⩾ c$

Question Number 126030 Answers: 1 Comments: 0

2^x =4x solve it please

$2^{x} = 4 x$ $solve it please$

Question Number 125990 Answers: 0 Comments: 0

Question Number 125960 Answers: 2 Comments: 0

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