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AlgebraQuestion and Answers: Page 254

Question Number 96131 Answers: 1 Comments: 0

(((x+4)^2 ))^(1/(3 )) + 4 (((x−3)^2 ))^(1/(3 )) + 5 ((x^2 +x−12))^(1/(3 )) = 0

$\sqrt[3]{{(x + 4)}^{2}} + 4 \sqrt[3]{{(x - 3)}^{2}} + 5 \sqrt[3]{x^{2} + x - 12} = 0$

Question Number 96072 Answers: 1 Comments: 0

(x^2 +24x+24).(x^2 +x+24)= 24x^2

$(x^{2} + 24 x + 24) . (x^{2} + x + 24) = {24 x}^{2}$

Question Number 96021 Answers: 0 Comments: 1

if p and q are two complex number and p×q=m ,m is a real number . is there always exists a p^(1/3) and q^(1/3) (we know p^(1/3) and q^(1/3) each has actually 3 values) such that p^(1/3) ×q^(1/3) =m^(1/3) .where m^(1/3) is real .?? how to prove it?

$if p and q are two complex number$ $and p \times q = m, m is a real number .$ $is there always exists a p^{\frac{1}{3}} and q^{\frac{1}{3}}$ $(we know p^{\frac{1}{3}} and q^{\frac{1}{3}} each has actually$ $3 values)$ $such that p^{\frac{1}{3}} \times q^{\frac{1}{3}} = m^{\frac{1}{3}} . where m^{\frac{1}{3}}$ $is real . ? ? how to prove it ?$

Question Number 95964 Answers: 0 Comments: 0

{ ((x^2 +y^2 =13)),((2x^2 +3y=2xy^2 )) :}

${\begin{cases} x^{2} + y^{2} = 13 \\ {2 x}^{2} + 3 y = {2 xy}^{2} \end{cases}$

Question Number 95967 Answers: 1 Comments: 1

Question Number 95920 Answers: 3 Comments: 0

((54+(√x)))^(1/(3 )) + ((54−(√x)))^(1/(3 )) = ((18))^(1/(3 )) x = ?

$\sqrt[3]{54 + \sqrt{x}} + \sqrt[3]{54 - \sqrt{x}} = \sqrt[3]{18}$ $x = ?$

Question Number 95919 Answers: 1 Comments: 0

∫3^(−4x^2 ) dx=? (0,∞)

$\int 3^{- {4 x}^{2}} dx = ? (0, \infty)$

Question Number 95898 Answers: 0 Comments: 0

x^2 +xy+(y^3 /3)=25 (y^2 /3)+z^2 =9 z^2 +zx+x^2 =16 so xy+2yz+3zx=?

$x^{2} + x y + \frac{y^{3}}{3} = 25$ $\frac{y^{2}}{3} + z^{2} = 9$ $z^{2} + z x + x^{2} = 16$ $s o x y + 2 y z + 3 z x = ?$

Question Number 95843 Answers: 1 Comments: 0

((((√(3x−7)))^2 −2)/(x−3)) ≤ ((3−((√x))^2 )/(x−3)) find the solution

$\frac{{(\sqrt{3 x - 7})}^{2} - 2}{x - 3} ⩽ \frac{3 - {(\sqrt{x})}^{2}}{x - 3}$ $find the solution$

Question Number 95789 Answers: 1 Comments: 1

Find the semi−interquartile range of of the following numbers: 15, 10, 9, 15, 15, 8, 10, 11, 8, 12, 11, 14, 9 and 15

$Find the semi - interquartile range of$ $of the following numbers :$ $15, 10, 9, 15, 15, 8, 10, 11, 8, 12, 11, 14,$ $9 and 15$

Question Number 95767 Answers: 1 Comments: 0

Question Number 95766 Answers: 0 Comments: 1

Solve the equation 2^(2x) − 5x^2 + 4 = 0

$Solve the equation$ $2^{2 x} - {5 x}^{2} + 4 = 0$

Question Number 95765 Answers: 0 Comments: 3

Sum the series: 2((1/(40)) + (1/(20)) + (1/(10)) + ... + n)

$Sum the series :$ $2 (\frac{1}{40} + \frac{1}{20} + \frac{1}{10} + . . . + n)$

Question Number 95742 Answers: 2 Comments: 2

(0/0)=2 ((100−100)/(100−100))=((10^2 −10^2 )/(10^2 −10^2 ))=(((10+10)(10−10))/(10(10−10))) ((20)/(10))=2 where is the mastike

$\frac{0}{0} = 2$ $\frac{100 - 100}{100 - 100} = \frac{10^{2} - 10^{2}}{10^{2} - 10^{2}} = \frac{(10 + 10) (10 - 10)}{10 (10 - 10)}$ $\frac{20}{10} = 2$ $where is the mastike$

Question Number 95668 Answers: 1 Comments: 2

Prove that: 2^(1/4) .4^(1/8) .8^(1/16) .16^(1/32) . ... ∞ = 2

$Prove that : 2^{1 / 4} . 4^{1 / 8} . 8^{1 / 16} . 16^{1 / 32} . . . . \infty = 2$

Question Number 95648 Answers: 0 Comments: 8

if 6^x =18 and 12^y =3 then x=? ((3y−4)/(y+4)) ((3y+2)/(y+2)) ((3y−3)/(3y−3)) ((3y+1)/(y+1))

$if 6^{x} = 18 and 12^{y} = 3$ $then x = ?$ $\frac{3 y - 4}{y + 4} \frac{3 y + 2}{y + 2} \frac{3 y - 3}{3 y - 3} \frac{3 y + 1}{y + 1}$

Question Number 95608 Answers: 3 Comments: 2

Question Number 95560 Answers: 1 Comments: 1

Question Number 95502 Answers: 1 Comments: 3

6 man + 8 woman ⇒working a job in 10 days 26 man + 48 woman ⇒ in 2 days if 15 man + 20 woman ⇒ ?? days

$6 man + 8 woman \Rightarrow working a job in 10 days$ $26 man + 48 woman \Rightarrow in 2 days$ $if 15 man + 20 woman \Rightarrow ? ? days$

Question Number 95469 Answers: 0 Comments: 1

(9b^2 −25) why is this inside the bracket as it is a diffetence of two squares?

$({9 b}^{2} - 25)$ $why is this inside the bracket as it is a diffetence of two squares ?$

Question Number 95447 Answers: 1 Comments: 0

can I write the solution of ay′′+by′+cy=0 y= { ((c_1 e^(((−b+(√(b^2 −4ac)))/2)x) +c_2 e^(((−b−(√(b^2 −4ac)))/2)x) ,when b^2 −4ac≠0)),((c_1 e^(((−b)/2)x) +c_2 xe^(((−b)/2)x) ,when b^2 −4ac=0)) :} in one sentence not in the form of piecewide-define function

$c a n I w r i t e t h e s o l u t i o n o f$ ${a y}^{″} + {b y}^{'} + c y = 0$ $y = {\begin{cases} c_{1} e^{\frac{- b + \sqrt{b^{2} - 4 a c}}{2} x} + c_{2} e^{\frac{- b - \sqrt{b^{2} - 4 a c}}{2} x}, w h e n b^{2} - 4 a c \neq 0 \\ c_{1} e^{\frac{- b}{2} x} + c_{2} {x e}^{\frac{- b}{2} x}, w h e n b^{2} - 4 a c = 0 \end{cases}$ $i n o n e s e n t e n c e$ $n o t i n t h e f o r m o f p i e c e w i d e - d e f i n e f u n c t i o n$

Question Number 95440 Answers: 1 Comments: 0

Question Number 95416 Answers: 1 Comments: 4

It takes 12 hours to fill a swimming pool using 2 pipes. If the larger pipe used , for 4 hours and the small pipe for 9 hours, only half the pool is filled. How long would it take for each pipe alone to fill the pool?

$It takes 12 hours to fill a swimming$ $pool using 2 pipes . If the larger$ $pipe used, for 4 hours and the$ $small pipe for 9 hours, only half$ $the pool is filled . How long would$ $it take for each pipe alone to$ $fill the pool ?$

Question Number 95394 Answers: 0 Comments: 31

Solve: x + y = 3 .... (i) x^y + y^x = 6 ..... (ii)

$Solve : x + y = 3 . . . . (i)$ $x^{y} + y^{x} = 6 . . . . . (ii)$

Question Number 95373 Answers: 1 Comments: 2

Find the value of m for which the roots of the equation x^3 + 6x^2 + 11x +m = 0 form a linear sequence.

$Find the value of m for which the roots$ $of the equation x^{3} + 6 x^{2} + 11 x + m = 0$ $form a linear sequence .$

Question Number 95328 Answers: 0 Comments: 3

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