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AlgebraQuestion and Answers: Page 261

Question Number 89268 Answers: 0 Comments: 0

Please help with this summation. Σ_(k = 0) ^n (− 1)^k ^n C_k y_(n − k) = ???

$Please help with this summation .$ $\underset{k = 0}{\sum^{n}} {(- 1)}^{k} \overset{n}{} C_{k} y_{n - k} = ? ? ?$

Question Number 89271 Answers: 0 Comments: 1

(3/4)×(8/9)×((15)/(16))×...×((2499)/(2500))

$\frac{3}{4} \times \frac{8}{9} \times \frac{15}{16} \times . . . \times \frac{2499}{2500}$

Question Number 89239 Answers: 0 Comments: 5

A new update has been released to fix issues with android 10. If you have android 10 phone please download latest update.

$A new update has been released to$ $fix issues with android 10 . If you$ $have android 10 phone please download$ $latest update .$

Question Number 89187 Answers: 0 Comments: 2

Question Number 89172 Answers: 1 Comments: 0

Question Number 89153 Answers: 1 Comments: 0

If P=((RE^2 )/((R+B)^2 )) make R the subject of the formula.

$If P = \frac{{RE}^{2}}{{(R + B)}^{2}} make R the subject of the formula .$

Question Number 89130 Answers: 0 Comments: 0

Question Number 89125 Answers: 1 Comments: 0

Question Number 89107 Answers: 0 Comments: 0

Question Number 89098 Answers: 0 Comments: 0

x=^( c−1) (√((ay−bz)/(cdy))) If a increases, what happens to x? Explain your answer.

$x =^{c - 1} \sqrt{\frac{a y - b z}{c d y}}$ $If a increases, what happens to x ?$ $Explain your answer .$

Question Number 89064 Answers: 1 Comments: 0

(√(1+(√(1+2(√(1+3(√(...)))))))) + (1/((√(1+2(√(1+3(√(1+4(√(...))))))))+(1/(√(1+3(√(1+4(√(1+5(√(...))))))))))) = ...

$\sqrt{1 + \sqrt{1 + 2 \sqrt{1 + 3 \sqrt{. . .}}}} + \frac{1}{\sqrt{1 + 2 \sqrt{1 + 3 \sqrt{1 + 4 \sqrt{. . .}}}} + \frac{1}{\sqrt{1 + 3 \sqrt{1 + 4 \sqrt{1 + 5 \sqrt{. . .}}}}}} = . . .$

Question Number 89086 Answers: 0 Comments: 1

show that (((2/3)−((5(√(33)))/(18))))^(1/3) +(((2/3)+((5(√(33)))/(18))))^(1/3) =1

$s h o w t h a t$ $\sqrt[3]{\frac{2}{3} - \frac{5 \sqrt{33}}{18}} + \sqrt[3]{\frac{2}{3} + \frac{5 \sqrt{33}}{18}} = 1$

Question Number 89070 Answers: 0 Comments: 0

(((√(a^2 +(b^2 /x^2 )))+(√(a^2 +b^2 x^2 )))/((√(a^2 +(b^2 /x^2 )))−(√(a^2 +b^2 x^2 )))) = ((a^2 /b^2 ))x x∈R^+ ; Express x in terms of a^2 , b^2 .

$\frac{\sqrt{a^{2} + \frac{b^{2}}{x^{2}}} + \sqrt{a^{2} + b^{2} x^{2}}}{\sqrt{a^{2} + \frac{b^{2}}{x^{2}}} - \sqrt{a^{2} + b^{2} x^{2}}} = (\frac{a^{2}}{b^{2}}) x$ $x \in R^{+}; E x p r e s s x i n t e r m s o f$ $a^{2}, b^{2} .$

Question Number 89032 Answers: 0 Comments: 0

find by using de moivre′s formula cos(2°)=?

$f i n d b y u s i n g d e {m o i v r e}^{'} s f o r m u l a$ $c o s (2 °) = ?$

Question Number 88937 Answers: 0 Comments: 0

Question Number 88921 Answers: 2 Comments: 0

find x,y x−2y−(√(xy))=0 (√(x−1))−(√(2y−1))=1

$f i n d x, y$ $x - 2 y - \sqrt{x y} = 0$ $\sqrt{x - 1} - \sqrt{2 y - 1} = 1$

Question Number 88881 Answers: 1 Comments: 0

Question Number 88873 Answers: 0 Comments: 1

3+(√(x^2 −5)) > ∣x−1∣

$3 + \sqrt{x^{2} - 5} > ∣ x - 1 ∣$

Question Number 88858 Answers: 0 Comments: 0

Question Number 88811 Answers: 1 Comments: 0

{ (((x+1)^2 (y+1)^2 =27xy)),(((x^2 +1)(y^2 +1) =10xy)) :}

${\begin{cases} {(x + 1)}^{2} {(y + 1)}^{2} = 27 x y \\ (x^{2} + 1) (y^{2} + 1) = 10 x y \end{cases}$

Question Number 88771 Answers: 0 Comments: 4

solve x^x^4 =64

$s o l v e$ $x^{x^{4}} = 64$

Question Number 88752 Answers: 1 Comments: 2

cos(𝛂)+cos(𝛃)+cos(𝛄)≤(3/2) prove the inequality

$\cos (α) + \cos (β) + \cos (γ) ⩽ \frac{3}{2}$ $prove the inequality$

Question Number 88678 Answers: 0 Comments: 8

Find (√i)+(√(−i))

$F i n d \sqrt{i} + \sqrt{- i}$

Question Number 88642 Answers: 1 Comments: 2

Question Number 88611 Answers: 0 Comments: 0

prove that ((1+p^2 +p^4 +......+p^(2n) )/(p+p^3 +p^5 +.....p^(2n−1) ))>((n+1)/(np))

$p r o v e t h a t$ $\frac{1 + p^{2} + p^{4} + . . . . . . + p^{2 n}}{p + p^{3} + p^{5} + . . . . . p^{2 n - 1}} > \frac{n + 1}{n p}$

Question Number 88610 Answers: 0 Comments: 2

is 1×1×1×..........=1^∞ or 1×1×1×1×1×..........=1

$i s 1 \times 1 \times 1 \times . . . . . . . . . . = 1^{\infty}$ $o r$ $1 \times 1 \times 1 \times 1 \times 1 \times . . . . . . . . . . = 1$

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