Question and Answers Forum

AlgebraQuestion and Answers: Page 265

Question Number 86396 Answers: 0 Comments: 0

Question Number 86298 Answers: 0 Comments: 5

let x^x^x^⋰ =2 x^2 =2 x=±(√2) then let x^x^x^⋰ =4 x^4 =4 x=±(4)^(1/4) =±(√2) so we had prove 2=4 right?

$l e t x^{x^{x^{\iddots}}} = 2$ $x^{2} = 2$ $x = \pm \sqrt{2}$ $t h e n l e t x^{x^{x^{\iddots}}} = 4$ $x^{4} = 4$ $x = \pm \sqrt[4]{4} = \pm \sqrt{2}$ $s o w e h a d p r o v e 2 = 4 r i g h t ?$

Question Number 86230 Answers: 1 Comments: 0

is (−1)^(m/n) =((((−1 )^m ))^(1/n) ) or =(((−1))^(1/n) )^m or both of them are fault and why ?

$i s {(- 1)}^{\frac{m}{n}} = (\sqrt[n]{{(- 1)}^{m}}) o r = {(\sqrt[n]{- 1})}^{m}$ $o r b o t h o f t h e m a r e f a u l t a n d w h y ?$

Question Number 86206 Answers: 0 Comments: 3

1.line:y=−x+4 ,meets : xy=1 at:A,B. ⇒ S_(OA^△ B) =? (O=origin of cordinates) 2.find :center area of region bonded by corve: (√(x/a))+(√(y/b))=1,and x,y axes. (a≠b)∈R^+

$1 . line : y = - x + 4, meets : xy = 1 at : A, B .$ $\Rightarrow S_{O \overset{△}{A B}} = ? (O = origin of cordinates)$ $2 . find : center area of region bonded by$ $corve : \sqrt{\frac{x}{a}} + \sqrt{\frac{y}{b}} = 1, and x, y axes .$ $(a \neq b) \in R^{+}$

Question Number 86141 Answers: 0 Comments: 5

A number n leaves a remainder of 22 when divided by 24 and remainder 30 when divided by 33. Find the least possible value of n

$A number n leaves a remainder of 22 when divided by 24 and$ $remainder 30 when divided by 33 . Find the least possible$ $value of n$

Question Number 86085 Answers: 1 Comments: 4

If X^2 +Y^2 =10 XY=5 Find (X^2 −Y^2 )

$If X^{2} + Y^{2} = 10$ $XY = 5$ $Find (X^{2} - Y^{2})$

Question Number 86042 Answers: 3 Comments: 0

solve: ⌊ (√x) ⌋=⌊(x/2)⌋

$s o l v e : ⌊ \sqrt{x} ⌋ = ⌊ \frac{x}{2} ⌋$

Question Number 86009 Answers: 1 Comments: 0

solve in R :[(x/2)]+[((2x)/3)]−x=0

$s o l v e i n R : [\frac{x}{2}] + [\frac{2 x}{3}] - x = 0$

Question Number 86000 Answers: 1 Comments: 0

solve the equation x^(1/3) =4

$s o l v e t h e e q u a t i o n x^{\frac{1}{3}} = 4$

Question Number 85930 Answers: 0 Comments: 1

Question Number 85902 Answers: 1 Comments: 15

find the coefficients of x^2 and x^3 terms in the expansion of (1+x)(1+2x)^2 (1+3x)^3 ...(1+100x)^(100)

$f i n d t h e c o e f f i c i e n t s o f x^{2} a n d x^{3}$ $t e r m s i n t h e e x p a n s i o n o f$ $(1 + x) {(1 + 2 x)}^{2} {(1 + 3 x)}^{3} . . . {(1 + 100 x)}^{100}$

Question Number 85871 Answers: 0 Comments: 3

Question Number 85864 Answers: 1 Comments: 0

simplify the expression (√(6+2(√(8(√3)−10)))) − (√(7−(√3))) in the form (√((√a)+b)) ?

$s i m p l i f y t h e e x p r e s s i o n$ $\sqrt{6 + 2 \sqrt{8 \sqrt{3} - 10}} - \sqrt{7 - \sqrt{3}} i n$ $t h e f o r m \sqrt{\sqrt{a} + b} ?$

Question Number 85854 Answers: 0 Comments: 2

If x,y,z ∈ R satisfy the equation x^4 + y^4 + z^4 = 4xyz −1 find minimum value of x + y + z

$If x, y, z \in R satisfy the equation$ $x^{4} + y^{4} + z^{4} = 4 xyz - 1$ $find minimum value of$ $x + y + z$

Question Number 85822 Answers: 2 Comments: 1

how to solve ((x−1))^(1/(3 )) + ((x−3))^(1/(3 )) + ((x−5))^(1/(3 )) = 0

$how to solve$ $\sqrt[3]{x - 1} + \sqrt[3]{x - 3} + \sqrt[3]{x - 5} = 0$

Question Number 85779 Answers: 0 Comments: 0

Question Number 85762 Answers: 0 Comments: 12

Question Number 85756 Answers: 0 Comments: 5

Question Number 85729 Answers: 0 Comments: 6

if march 24, 2020 is Tuesday, then march 24, 2032 is the day ?

$if march 24, 2020 is Tuesday,$ $then march 24, 2032 is the day ?$

Question Number 85696 Answers: 0 Comments: 0

Montrer que: (√5)+(√(30))+(√(50))<(√(10))+(√(20))+(√(60)) {niveau second)

$Montrer que :$ $\sqrt{5} + \sqrt{30} + \sqrt{50} < \sqrt{10} + \sqrt{20} + \sqrt{60}$ ${niveau second)$

Question Number 85664 Answers: 0 Comments: 2

Show that a group order 100 is not simple

$S how that a group order 100 is not simple$

Question Number 85655 Answers: 0 Comments: 0

Question Number 85624 Answers: 0 Comments: 0

Question Number 85554 Answers: 0 Comments: 1

2x^2 +5x+7=0

$2 x^{2} + 5 x + 7 = 0$

Question Number 85532 Answers: 1 Comments: 0

Find the term independent of x in the expression of (2x−(1/(2x)))^9

$F i n d t h e t e r m i n d e p e n d e n t o f x i n t h e e x p r e s s i o n o f {(2 x - \frac{1}{2 x})}^{9}$

Question Number 85490 Answers: 0 Comments: 3

Given that the expression 2x^3 +px^2 −8x+9 is exactly divisable by x^2 −6x+5, find the value of p and q. Hence factorise the expression fully

$G i v e n t h a t t h e e x p r e s s i o n 2 x^{3} + {p x}^{2} - 8 x + 9 i s e x a c t l y d i v i s a b l e b y x^{2} - 6 x + 5, f i n d t h e v a l u e o f p a n d q . H e n c e f a c t o r i s e t h e e x p r e s s i o n f u l l y$

Pg 260 Pg 261 Pg 262 Pg 263 Pg 264 Pg 265 Pg 266 Pg 267 Pg 268 Pg 269

Contact: info@tinkutara.com