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AlgebraQuestion and Answers: Page 59

Question Number 194586 Answers: 1 Comments: 2

abc = e^3 + d^3 + f^3 edf = a^3 + b^3 + c^3 find: abc and edf

$abc = e^{3} + d^{3} + f^{3}$ $edf = a^{3} + b^{3} + c^{3}$ $find : abc and edf$

Question Number 194579 Answers: 2 Comments: 0

if u_n =(1/( (√5)))[(((1+(√5))/2))^n −(((1−(√5))/2))^n ] then u_(n+1) =u_n +u_(n−1) ? ; n=0,1,2,..

$i f u_{n} = \frac{1}{\sqrt{5}} [{(\frac{1 + \sqrt{5}}{2})}^{n} - {(\frac{1 - \sqrt{5}}{2})}^{n}]$ $t h e n u_{n + 1} = u_{n} + u_{n - 1} ?; n = 0, 1, 2, . .$

Question Number 194573 Answers: 0 Comments: 0

Question Number 194559 Answers: 2 Comments: 0

repeat question Shiw that : Σ_(i=1) ^n ((1/(2i−1))−(1/(2i)))=Σ_(i=1) ^n (1/(n+i)) ?

$r e p e a t q u e s t i o n$ $S h i w t h a t :$ $\underset{i = 1}{\sum^{n}} (\frac{1}{2 i - 1} - \frac{1}{2 i}) = \underset{i = 1}{\sum^{n}} \frac{1}{n + i} ?$

Question Number 194526 Answers: 2 Comments: 0

((f(x+1))/(f(x)))=x^(2 ) f(x)=? ((f(6))/(f(3)))=?

$\frac{f (x + 1)}{f (x)} = x^{2} f (x) = ?$ $\frac{f (6)}{f (3)} = ?$

Question Number 194522 Answers: 7 Comments: 0

Question Number 194509 Answers: 2 Comments: 0

Question Number 194491 Answers: 1 Comments: 0

x=(√(4+(√(5(√3) +5(√(48−10(√(7+4(√3))))))))) determinant (((2x−1=?)))

$x = \sqrt{4 + \sqrt{5 \sqrt{3} + 5 \sqrt{48 - 10 \sqrt{7 + 4 \sqrt{3}}}}}$ $\begin{matrix} 2 x - 1 = ? \end{matrix}$

Question Number 194455 Answers: 1 Comments: 0

Question Number 194444 Answers: 1 Comments: 0

Question Number 194422 Answers: 1 Comments: 0

What books use for studying inequalities for beginners

$W h a t b o o k s u s e f o r s t u d y i n g i n e q u a l i t i e s$ $f o r b e g i n n e r s$

Question Number 194389 Answers: 1 Comments: 0

(√(√(49+20(√6))))=?

$\sqrt{\sqrt{49 + 20 \sqrt{6}}} = ?$

Question Number 194383 Answers: 0 Comments: 0

Question Number 194373 Answers: 0 Comments: 0

Show Σ_(i=1) ^n ((1/(2i−1))− (1/(2i)))=Σ_(i=1) ^n (1/(n+i))

$S h o w$ $\underset{i = 1}{\sum^{n}} (\frac{1}{2 i - 1} - \frac{1}{2 i}) = \underset{i = 1}{\sum^{n}} \frac{1}{n + i}$

Question Number 194326 Answers: 1 Comments: 0

(√(((√(x^2 +66^2 +x))/x) )) −(√(x(√(x^2 +66^2 ))−x^2 )) = 5

$\sqrt{\frac{\sqrt{x^{2} + 66^{2} + x}}{x}} - \sqrt{x \sqrt{x^{2} + 66^{2}} - x^{2}} = 5$

Question Number 194322 Answers: 0 Comments: 0

Question Number 194321 Answers: 1 Comments: 0

find min −(((x−y)(((xy)/4)−4)^2 )/(xy)) s. t. x>0>y

$find \min - \frac{(x - y) {(\frac{x y}{4} - 4)}^{2}}{x y}$ $s . t . x > 0 > y$

Question Number 194316 Answers: 0 Comments: 1

if x∈R & x^x^6 =((√2))^(√2) ⇒ x=?

$i f x \in R & x^{x^{6}} = {(\sqrt{2})}^{\sqrt{2}} \Rightarrow x = ?$

Question Number 194295 Answers: 1 Comments: 0

Question Number 194238 Answers: 1 Comments: 0

Question Number 194226 Answers: 3 Comments: 0

If x^2 − 65x = 64(√x) then (√(x − (√x) )) = ?

$If x^{2} - 65 x = 64 \sqrt{x} then \sqrt{x - \sqrt{x}} = ?$

Question Number 194219 Answers: 1 Comments: 0

Question Number 194218 Answers: 1 Comments: 2

Question Number 194216 Answers: 1 Comments: 0

Question Number 194209 Answers: 0 Comments: 0

((1+kx))^(1/3) +x = 1 has two real roots . ⇒ k=? kx+1= 1−3x+3x^2 −x^( 3) x^( 3) −3x^( 2) + (k+3)x=0 x=0 x^( 2) −3x +k+3=0 1: Δ=0 9 − 4k −12=0 k= ((−3)/4) 2: k=−3 ⇒ x=0 is a root of x^( 2) −3x+k+3=0 ∴ k= ((−3)/4) or k=−3

$\sqrt[3]{1 + k x} + x = 1 h a s$ $t w o r e a l r o o t s . \Rightarrow k = ?$ $k x + 1 = 1 - 3 x + 3 x^{2} - x^{3}$ $x^{3} - 3 x^{2} + (k + 3) x = 0$ $x = 0$ $x^{2} - 3 x + k + 3 = 0$ $1 : Δ = 0$ $9 - 4 k - 12 = 0$ $k = \frac{- 3}{4}$ $2 : k = - 3 \Rightarrow x = 0 i s a r o o t o f$ $x^{2} - 3 x + k + 3 = 0$ $∴ k = \frac{- 3}{4} o r k = - 3$

Question Number 194207 Answers: 0 Comments: 0

Solve for x x^(x−4) =(√(3 ))

$Solve for x$ $x^{x - 4} = \sqrt{3}$

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