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AlgebraQuestion and Answers: Page 82

Question Number 184401 Answers: 2 Comments: 3

U_n = ((((−4)^(n+1) −1)/(1−(−4)^n )))U_(n−1) with U_0 =1 find U_(n ) in terms of n (question Q173132 reposted)

$U_{n} = (\frac{{(- 4)}^{n + 1} - 1}{1 - {(- 4)}^{n}}) U_{n - 1} w i t h U_{0} = 1$ $f i n d U_{n} i n t e r m s o f n$ $(q u e s t i o n Q 173132 r e p o s t e d)$

Question Number 184384 Answers: 0 Comments: 7

Question Number 184351 Answers: 5 Comments: 0

f(x)=((a^x +b^x +c^x )/x) with a+b+c=0 prove f(7)=f(5)×f(2)

$f (x) = \frac{a^{x} + b^{x} + c^{x}}{x} w i t h a + b + c = 0$ $p r o v e f (7) = f (5) \times f (2)$

Question Number 184305 Answers: 1 Comments: 0

if: f(x) = x^2 + 2x find x: f(f(f(x + 2))) = 99 999 999

$i f : f (x) = x^{2} + 2 x$ $f i n d x :$ $f (f (f (x + 2))) = 99 999 999$

Question Number 184304 Answers: 2 Comments: 0

Question Number 184302 Answers: 1 Comments: 0

Question Number 184280 Answers: 1 Comments: 13

Given { ((a_0 =1)),((a_(n+1) =(1/2)(3a_n +(√(5a_n ^2 −4)) ))) :} ∀n≥0 , n∈I find a_n .

$G i v e n {\begin{cases} a_{0} = 1 \\ a_{n + 1} = \frac{1}{2} (3 a_{n} + \sqrt{5 a_{n}^{2} - 4}) \end{cases}$ $\forall n ⩾ 0, n \in I$ $f i n d a_{n} .$

Question Number 184270 Answers: 2 Comments: 0

((−64))^(1/6) ∙((−128))^(1/7) =?

$\sqrt[6]{- 64} \cdot \sqrt[7]{- 128} = ?$

Question Number 184258 Answers: 2 Comments: 0

2yz−4z+2x−2=0 2xz−2z+2y−4=0 2xy−4x−2y+2z+4=0 how to find the all values of the (x,y,z) ?

$2 yz - 4 z + 2 x - 2 = 0$ $2 xz - 2 z + 2 y - 4 = 0$ $2 xy - 4 x - 2 y + 2 z + 4 = 0$ $how to find the all values of the (x, y, z) ?$

Question Number 184251 Answers: 6 Comments: 0

If x (√y) = 2904 Find: y=?

$If x \sqrt{y} = 2904$ $Find : y = ?$

Question Number 184242 Answers: 1 Comments: 0

Question Number 184160 Answers: 4 Comments: 1

Given { ((a_0 =1)),((a_(n+1) =(1/2)(3a_n +(√(5a_n ^2 −4)) ))) :} ∀n≥0 , n∈I find a_n .

$G i v e n {\begin{cases} a_{0} = 1 \\ a_{n + 1} = \frac{1}{2} (3 a_{n} + \sqrt{5 a_{n}^{2} - 4}) \end{cases}$ $\forall n ⩾ 0, n \in I$ $f i n d a_{n} .$

Question Number 184095 Answers: 2 Comments: 0

Question Number 184085 Answers: 1 Comments: 0

(y^2 + xy^2 )y^′ + x^2 − yx^2 = 0

$(y^{2} + {xy}^{2}) y^{^{'}} + x^{2} - {yx}^{2} = 0$

Question Number 184084 Answers: 1 Comments: 0

Question Number 184083 Answers: 1 Comments: 0

f(x)= x^( 3) +3x^( 2) −ax is decreasing on [ −1 , 2] then which is correct... 1: [ −3 ,24] 2: [ 24 , +∞) 3: (−∞ ,−3] 4 :(−∞, −3]∪[24, +∞)

$f (x) = x^{3} + 3 x^{2} - a x i s$ $d e c r e a s i n g o n [- 1, 2]$ $t h e n w h i c h i s c o r r e c t . . .$ $1 : [- 3, 24]$ $2 : [24, + \infty)$ $3 : (- \infty, - 3]$ $4 : (- \infty, - 3] \cup [24, + \infty)$

Question Number 184019 Answers: 1 Comments: 2

{ ((y^x = 64)),((y^((x + 1)/(x − 1)) = 16)) :} find “x”

${\begin{cases} y^{x} = 64 \\ y^{\frac{x + 1}{x - 1}} = 16 \end{cases}$ $f i n d ‘ ‘ x^{″}$

Question Number 183864 Answers: 4 Comments: 2

Question Number 183848 Answers: 2 Comments: 1

Question Number 183847 Answers: 5 Comments: 0

Question Number 183846 Answers: 4 Comments: 0

Question Number 183843 Answers: 1 Comments: 0

Question Number 183835 Answers: 2 Comments: 0

Resoudre le systeme abc =30 a+b+c =10 ab+bc+ac=31

$R e s o u d r e l e s y s t e m e$ $abc = 30$ $a + b + c = 10$ $ab + bc + ac = 31$

Question Number 183825 Answers: 1 Comments: 0

solve for x by using lambert function 2^x +3x=8

$s o l v e f o r x b y u s i n g l a m b e r t f u n c t i o n$ $2^{x} + 3 x = 8$

Question Number 183777 Answers: 2 Comments: 1

Question Number 183769 Answers: 0 Comments: 4

solve for x: x^x^x =2^(2048) by using lambert function

$s o l v e f o r x :$ $x^{x^{x}} = 2^{2048}$ $b y u s i n g l a m b e r t f u n c t i o n$

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