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Question Number 70008 Answers: 1 Comments: 0

Find the value of x. log_8 x + log_4 x + log_2 x = 11.

$Find the value of x .$ $\log_{8} x + \log_{4} x + \log_{2} x = 11 .$

Question Number 70017 Answers: 0 Comments: 2

Solution- log_8 x+log_4 x+log_2 x=11 ⇒(1/(log_x 8))+(1/(log_x 4))+(1/(log_x 2))=11 ⇒(1/(log_x 2^3 ))+(1/(log_x 2^2 ))+(1/(log_x 2))=11 ⇒(1/(3log_x 2))+(1/(2log_x 2))+(1/(log_x 2))=11 ⇒((1/3)+(1/2)+1)(1/(log_x 2))=11 ⇒((11)/6)×(1/(log_x 2))=11 ⇒(1/(log_x 2))=11×(6/(11)) ⇒log_2 x=6 ⇒x=2^6 ∴x=64 is this rule correct????

Question Number 70003 Answers: 0 Comments: 3

Let f(x)=3^(x−1) , g(x)=3^x and h(x)=4 determine the values of x for which: f(x)+g(x)≥h(x).

$L e t f (x) = 3^{x - 1}, g (x) = 3^{x} a n d h (x) = 4$ $d e t e r m i n e t h e v a l u e s o f x f o r w h i c h :$ $f (x) + g (x) ⩾ h (x) .$

Question Number 69995 Answers: 4 Comments: 0

1. { (((√(x^2 +y^2 ))+(√(x^2 −y^2 ))=a)),(((√(x+y))+(√(x−y))=b)) :} [a,b∈R^+ ] 2. { (((√((√x)+y))+(√(x+(√y)))=a)),(((√((√x)−y))+(√(x−(√y)))=b)) :} 3. { ((x^2 +y^2 =(a−b)xy)),((x^3 +y^3 =ab(x−y))) :} 4. { ((x+y+z=a)),((x^2 +y^2 +z^2 =b)),((x^3 +y^3 +z^3 =abxyz)) :} 5. (√(x^2 +(√x)))+(√(x^2 −(√x)))=2 6. (√(x^2 +x+1))+(√(x^2 +x−1))+(√(x^2 −x−1))=1 7. 16^(sin^2 x) +16^(cos^2 x) =10 8. 2^(lnx) =x.ln(x+(√2))

$1 . {\begin{cases} \sqrt{x^{2} + y^{2}} + \sqrt{x^{2} - y^{2}} = a \\ \sqrt{x + y} + \sqrt{x - y} = b \end{cases} [a, b \in R^{+}]$ $2 . {\begin{cases} \sqrt{\sqrt{x} + y} + \sqrt{x + \sqrt{y}} = a \\ \sqrt{\sqrt{x} - y} + \sqrt{x - \sqrt{y}} = b \end{cases}$ $3 . {\begin{cases} x^{2} + y^{2} = (a - b) xy \\ x^{3} + y^{3} = ab (x - y) \end{cases}$ $4 . {\begin{cases} x + y + z = a \\ x^{2} + y^{2} + z^{2} = b \\ x^{3} + y^{3} + z^{3} = abxyz \end{cases}$ $5 . \sqrt{x^{2} + \sqrt{x}} + \sqrt{x^{2} - \sqrt{x}} = 2$ $6 . \sqrt{x^{2} + x + 1} + \sqrt{x^{2} + x - 1} + \sqrt{x^{2} - x - 1} = 1$ $7 . 16^{\sin^{2} x} + 16^{\cos^{2} x} = 10$ $8 . 2^{lnx} = x . \ln (x + \sqrt{2})$

Question Number 69979 Answers: 0 Comments: 2

Using the definition calculate the derivative at point x=2 f(x)=2x^3

$U s i n g t h e d e f i n i t i o n c a l c u l a t e t h e$ $d e r i v a t i v e a t p o i n t x = 2$ $f (x) = 2 x^{3}$

Question Number 69974 Answers: 0 Comments: 3

Identify domain and range of this function that f(x)= ln((4−x)/(4+x)).

$Identify domain and range of this$ $function that f (x) = \ln \frac{4 - x}{4 + x} .$

Question Number 69954 Answers: 0 Comments: 3

A= (((1 2)),((0 1)) ) find A^n

$A = (\begin{matrix} 1 2 \\ 0 1 \end{matrix}) find A^{n}$

Question Number 69953 Answers: 0 Comments: 5

if tan θ+sec θ= (√3) than find out the value of _ θ where 0^o ≤θ≤2π.

$if \tan θ + \sec θ = \sqrt{3} than find out the$ $value of \underset{}{} θ where 0^{o} ⩽ θ ⩽ 2 π .$

Question Number 69944 Answers: 0 Comments: 4

If 2^x =0 find x

$If 2^{x} = 0 find x$

Question Number 69939 Answers: 2 Comments: 12

x,y,z ∈ Z^+ find all solutions of xy=(x+y)z

$x, y, z \in Z^{+}$ $f i n d a l l s o l u t i o n s o f x y = (x + y) z$

Question Number 69912 Answers: 1 Comments: 0

(√(xy)) + 3 = y Find (dy/dx) .

$\sqrt{x y} + 3 = y$ $F i n d \frac{d y}{d x} .$

Question Number 69906 Answers: 1 Comments: 7

Notifications are working now. We are still working on other issues. No app update is needed. The changes were only on server side.

$Notifications are working now .$ $We are still working on other issues .$ $No app update is needed . The changes$ $were only on server side .$

Question Number 69901 Answers: 1 Comments: 2

Question Number 70718 Answers: 1 Comments: 1

∫_0 ^1 ((tan^(−1) x)/(1+x))dx

$\int_{0}^{1} \frac{\tan^{- 1} x}{1 + x} dx$

Question Number 69894 Answers: 0 Comments: 3

∫ ((2x^5 −x)/(x^3 −2))dx

$\int \frac{2 x^{5} - x}{x^{3} - 2} d x$

Question Number 69966 Answers: 0 Comments: 1

Question Number 69878 Answers: 0 Comments: 3

Question Number 69874 Answers: 0 Comments: 3

Hi We are still working on solving android api update and notification related issues. The solution of these problem will take a few more weeks. Sorry about the inconvenience caused and we thank you for your patience.

$Hi$ $We are still working on solving$ $android api update and notification$ $related issues . The solution of these$ $problem will take a few more weeks .$ $Sorry about the inconvenience$ $caused and we thank you for your$ $patience .$

Question Number 69871 Answers: 1 Comments: 0

Here, m^2 −n^(2 ) = 4(√(mn ))and tanθ+sinθ= m then prove that, tanθ−sinθ= n.

$Here, m^{2} - n^{2} = 4 \sqrt{mn} and \tan θ + \sin θ = m$ $then prove that, \tan θ - \sin θ = n .$

Question Number 69873 Answers: 0 Comments: 1

Question Number 69866 Answers: 1 Comments: 0

Question Number 69851 Answers: 0 Comments: 0

A convex mirror of radius of curvature 30cm forms a real image 20cm from its surface.Find whether the imavect is erect or inverted.Please explain how possible this is. Thanks in advance.

$A c o n v e x m i r r o r o f r a d i u s o f c u r v a t u r e$ $30 c m f o r m s a r e a l i m a g e 20 c m f r o m i t s$ $s u r f a c e . F i n d w h e t h e r t h e i m a v e c t i s$ $e r e c t o r i n v e r t e d . P l e a s e e x p l a i n h o w$ $p o s s i b l e t h i s i s .$ $T h a n k s i n a d v a n c e .$

Question Number 69847 Answers: 1 Comments: 0

A plane is travelling at 500km/hr eastward. wind blows at 90km/hr southward. find the velocity and direction if the plane rlative to the ground.

$A p l a n e i s t r a v e l l i n g a t 500 k m / h r e a s t w a r d .$ $w i n d b l o w s a t 90 k m / h r s o u t h w a r d .$ $f i n d t h e v e l o c i t y a n d d i r e c t i o n i f t h e p l a n e r l a t i v e t o t h e g r o u n d .$

Question Number 69846 Answers: 1 Comments: 0

Find the x−component and y−component of a 25N force acting at 210° angle

$F i n d t h e x - c o m p o n e n t a n d y - c o m p o n e n t o f a 25 N f o r c e a c t i n g a t 210 ° a n g l e$

Question Number 69836 Answers: 1 Comments: 2

Question Number 69829 Answers: 2 Comments: 2

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