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AllQuestion and Answers: Page 1567

Question Number 47817 Answers: 1 Comments: 1

Question Number 47815 Answers: 1 Comments: 3

Question Number 47814 Answers: 1 Comments: 1

A boy runs towards a man standing 150m away.Speed of boy is 5m/s and that of man is 10m/s.The time and distance of their meeting from the boy^. s position are a)15s b)5s and 150m c)10s and 50m d)10s and 100m

$A b o y r u n s t o w a r d s a m a n s t a n d i n g$ $150 m a w a y . S p e e d o f b o y i s 5 m / s$ $a n d t h a t o f m a n i s 10 m / s . T h e$ $t i m e a n d d i s t a n c e o f t h e i r m e e t i n g$ $f r o m t h e {b o y}^{.} s p o s i t i o n a r e$ $a) 15 s b) 5 s a n d 150 m c) 10 s a n d 50 m$ $d) 10 s a n d 100 m$

Question Number 47807 Answers: 1 Comments: 0

sin xy^2 =y^2 +2x diferential express is

$\sin {x y}^{2} = y^{2} + 2 x$ $diferential e x p r e s s is$

Question Number 47850 Answers: 1 Comments: 2

calculate A_p =∫_0 ^1 ((x^p −1)/(ln(x)))dx with p>0.

$c a l c u l a t e A_{p} = \int_{0}^{1} \frac{x^{p} - 1}{l n (x)} d x w i t h p > 0 .$

Question Number 47788 Answers: 0 Comments: 1

Question Number 47779 Answers: 0 Comments: 1

Question Number 47778 Answers: 1 Comments: 0

f(x)=2x^3 +x^2 −2x−1 f^(−1) (x)=...

$f (x) = 2 x^{3} + x^{2} - 2 x - 1$ $f^{- 1} (x) = . . .$

Question Number 47775 Answers: 2 Comments: 1

Question Number 47771 Answers: 0 Comments: 0

∫_0 ^(π/2) (x/(tanx))dx

$\int_{0}^{\frac{π}{2}} \frac{x}{t a n x} d x$

Question Number 47770 Answers: 1 Comments: 3

∫_0 ^1 ((x^2 −1)/(lnx))dx

$\int_{0}^{1} \frac{x^{2} - 1}{l n x} d x$

Question Number 47768 Answers: 0 Comments: 3

Somebody know spanish?

$Somebody know spanish ?$

Question Number 47810 Answers: 1 Comments: 1

A mobike rider moving from A to B with speed 20km/h notices that a bus goes past it every 21 minute in the direction of his motion and every 7 minutes in the opposite direction.Velocity of the bus is a)25km/h b)35km/h c)30km/h d)40km/h

$A m o b i k e r i d e r m o v i n g f r o m A t o B$ $w i t h s p e e d 20 k m / h n o t i c e s t h a t a$ $b u s g o e s p a s t i t e v e r y 21 m i n u t e i n$ $t h e d i r e c t i o n o f h i s m o t i o n a n d$ $e v e r y 7 m i n u t e s i n t h e o p p o s i t e$ $d i r e c t i o n . V e l o c i t y o f t h e b u s i s$ $a) 25 k m / h b) 35 k m / h c) 30 k m / h$ $d) 40 k m / h$

Question Number 47743 Answers: 2 Comments: 0

∫(dx/(x^n −x)) the problems i have posted are tricky...

$\int \frac{d x}{x^{n} - x}$ $t h e p r o b l e m s i h a v e p o s t e d a r e t r i c k y . . .$

Question Number 47737 Answers: 1 Comments: 0

I = ∫_0 ^( L/2) ((Rz^2 )/((d^2 +z^2 )(√(d^2 +z^2 −R^2 )))) dz Find I .

$I = \int_{0}^{L / 2} \frac{{R z}^{2}}{(d^{2} + z^{2}) \sqrt{d^{2} + z^{2} - R^{2}}} d z$ $F i n d I .$

Question Number 47735 Answers: 1 Comments: 5

Question Number 47727 Answers: 1 Comments: 0

Find the value of a for a : 4 : : 5 : 10

$Find the value of a for$ $a : 4 : : 5 : 10$

Question Number 47725 Answers: 1 Comments: 2

Question Number 47713 Answers: 0 Comments: 4

Question Number 47712 Answers: 0 Comments: 0

show that ^(^2 C_2 ) C_n = (1/((1−n)!(n−1)(n−2)(n−3)...3(2)(1)))

$s h o w t h a t$ $^{^{2} C_{2}} C_{n} = \frac{1}{(1 - n)! (n - 1) (n - 2) (n - 3) . . . 3 (2) (1)}$

Question Number 47720 Answers: 2 Comments: 0

find ∫ ln(1+x^3 )dx

$f i n d \int l n (1 + x^{3}) d x$

Question Number 47740 Answers: 2 Comments: 0

∫(dx/(x(x+1)(x+2)(x+3)...(x+n)))

$\int \frac{d x}{x (x + 1) (x + 2) (x + 3) . . . (x + n)}$

Question Number 47697 Answers: 1 Comments: 1

Question Number 47677 Answers: 0 Comments: 3

∫x^(x ) dx=

$\int x^{x} dx =$

Question Number 47675 Answers: 2 Comments: 0

A particle of mass 4kg was at rest a a point of position vector i +4j. A force F was applied to it and it moved at a velocity of (3i + 7j)ms^(−1) after a time of 5seconds. Find a) the magnitude of F b) The speed at which it moves,Hence, c) The distance it covered.

$A p a r t i c l e o f m a s s 4 k g w a s a t r e s t a a p o i n t o f p o s i t i o n v e c t o r$ $i + 4 j . A f o r c e F w a s a p p l i e d t o i t a n d i t m o v e d a t a v e l o c i t y$ $o f (3 i + 7 j) {m s}^{- 1} a f t e r a t i m e o f 5 s e c o n d s . F i n d$ $a) t h e m a g n i t u d e o f F$ $b) T h e s p e e d a t w h i c h i t m o v e s, H e n c e,$ $c) T h e d i s t a n c e i t c o v e r e d .$

Question Number 47659 Answers: 2 Comments: 0

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