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In a quadrilateral ABCD, it is given that AB is parallel to CD and the diagonals AC and BD are perpendicular to each other. Show that (a) AD.BC ≥ AB.CD; (b) AD + BC ≥ AB + CD.

$In a quadrilateral A B C D, it is given$ $that A B is parallel to C D and the$ $diagonals A C and B D are perpendicular$ $to each other .$ $Show that$ $(a) A D . B C ⩾ A B . C D;$ $(b) A D + B C ⩾ A B + C D .$

Question Number 22503 Answers: 1 Comments: 4

If (a + bx)^(−2) = (1/4) − 3x + ..., then (a, b) =

$If {(a + b x)}^{- 2} = \frac{1}{4} - 3 x + . . ., then (a, b) =$

Question Number 22499 Answers: 1 Comments: 1

A cylinder of weight 200 N is supported on a smooth horizontal plane by a light cord AC and pulled with force of 400 N. The normal reaction at B is equal to

$A cylinder of weight 200 N is supported$ $on a smooth horizontal plane by a light$ $cord A C and pulled with force of 400 N .$ $The normal reaction at B is equal to$

Question Number 22492 Answers: 1 Comments: 1

A ball of mass 400 g travels horizontally along the ground and collides with a wall. The velocity-time graph below represents the motion of the ball for the first 1.2 seconds. The magnitude of average force between the ball and the wall is

$A ball of mass 400 g travels horizontally$ $along the ground and collides with a$ $wall . The velocity - time graph below$ $represents the motion of the ball for the$ $first 1.2 seconds .$ $The magnitude of average force between$ $the ball and the wall is$

Question Number 22491 Answers: 1 Comments: 0

The coefficient of x^r in the expansion of (1 − 2x)^(−1/2) is (1) (((2r)!)/((r!)^2 )) (2) (((2r)!)/(2^r (r!)^2 )) (3) (((2r)!)/((r!)^2 2^(2r) )) (4) (((2r)!)/(2^r (r + 1)!(r − 1)!))

$The coefficient of x^{r} in the expansion of$ ${(1 - 2 x)}^{- 1 / 2} is$ $(1) \frac{(2 r)!}{{(r!)}^{2}}$ $(2) \frac{(2 r)!}{2^{r} {(r!)}^{2}}$ $(3) \frac{(2 r)!}{{(r!)}^{2} 2^{2 r}}$ $(4) \frac{(2 r)!}{2^{r} (r + 1)! (r - 1)!}$

Question Number 22487 Answers: 1 Comments: 1

Question Number 22483 Answers: 0 Comments: 0

Predict the density of Cs from the density of the following elements K 0.86 g/cm^3 Ca 1.548 g/cm^3 Sc 2.991 g/cm^3 Rb 1.532 g/cm^3 Sr 2.68 g/cm^3 Y 4.34 g/cm^3 Cs ? Ba 3.51 g/cm^3 La 6.16 g/cm^3

$Predict the density of Cs from the$ $density of the following elements$ $K 0.86 g / {cm}^{3} Ca 1.548 g / {cm}^{3}$ $Sc 2.991 g / {cm}^{3} Rb 1.532 g / {cm}^{3}$ $Sr 2.68 g / {cm}^{3} Y 4.34 g / {cm}^{3}$ $Cs ? Ba 3.51 g / {cm}^{3}$ $La 6.16 g / {cm}^{3}$

Question Number 22481 Answers: 1 Comments: 1

Question Number 22479 Answers: 0 Comments: 2

A ladder of mass m is leaning against a wall. It is in static equilibrium making an angle θ with the horizontal floor. The coefficient of friction between the wall and the ladder is μ_1 and that between the floor and the ladder is μ_2 . The normal reaction of the wall on the ladder is N_1 and that of the floor is N_2 . If the ladder is about to slip, then (1) μ_1 = 0, μ_2 ≠ 0 and N_2 tan θ = mg/2 (2) μ_1 ≠ 0, μ_2 = 0 and N_1 tan θ = mg/2 (3) μ_1 ≠ 0, μ_2 ≠ 0 and N_2 = ((mg)/(1 + μ_1 μ_2 )) (4) μ_1 = 0, μ_2 ≠ 0 and N_1 tan θ = ((mg)/2)

$A ladder of mass m is leaning against a$ $wall . It is in static equilibrium making$ $an angle θ with the horizontal floor .$ $The coefficient of friction between the$ $wall and the ladder is μ_{1} and that$ $between the floor and the ladder is μ_{2} .$ $The normal reaction of the wall on the$ $ladder is N_{1} and that of the floor is N_{2} .$ $If the ladder is about to slip, then$ $(1) μ_{1} = 0, μ_{2} \neq 0 and N_{2} \tan θ = m g / 2$ $(2) μ_{1} \neq 0, μ_{2} = 0 and N_{1} \tan θ = m g / 2$ $(3) μ_{1} \neq 0, μ_{2} \neq 0 and N_{2} = \frac{m g}{1 + μ_{1} μ_{2}}$ $(4) μ_{1} = 0, μ_{2} \neq 0 and N_{1} \tan θ = \frac{m g}{2}$

Question Number 22478 Answers: 0 Comments: 1

{ ((x+y^2 +z^3 =3)),((y+z^2 +x^3 =3)),((z+x^2 +z^3 =3)) :} trouver les solutions positives

${\begin{cases} x + y^{2} + z^{3} = 3 \\ y + z^{2} + x^{3} = 3 \\ z + x^{2} + z^{3} = 3 \end{cases}$ $t r o u v e r l e s s o l u t i o n s p o s i t i v e s$

Question Number 22696 Answers: 1 Comments: 5

A force F^→ = 2xj^∧ newton acts in a region where a particle moves anticlockwise in a square loop of 2 m in x-y plane. Calculate the total amount of work done. Is this force a conservative force or a non-conservative force?

$A force \vec{F} = 2 x \overset{\land}{j} newton acts in a region$ $where a particle moves anticlockwise$ $in a square loop of 2 m in x - y plane .$ $Calculate the total amount of work$ $done . Is this force a conservative force$ $or a non - conservative force ?$

Question Number 22475 Answers: 0 Comments: 1

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