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AllQuestion and Answers: Page 1853

Question Number 18640    Answers: 1   Comments: 1

Question Number 18639    Answers: 0   Comments: 0

∫(√(1+x^4 )) dx please solve this question.

1+x4dxpleasesolvethisquestion.

Question Number 18632    Answers: 0   Comments: 0

x − 5x + 3 = 7 −4x = 4 x = −1

x5x+3=74x=4x=1

Question Number 18625    Answers: 1   Comments: 1

x−5×+3=7

x5×+3=7

Question Number 18624    Answers: 1   Comments: 0

Argon diffuses through a hole under prescribed condition of temperature and pressure at the rate of 3cm^3 per velocity. At what velocity will helium diffuse through the same hole under the same condition (Ar = 29.94 g, He = 4g).

Argondiffusesthroughaholeunderprescribedconditionoftemperatureandpressureattherateof3cm3pervelocity.Atwhatvelocitywillheliumdiffusethroughthesameholeunderthesamecondition(Ar=29.94g,He=4g).

Question Number 18627    Answers: 1   Comments: 1

lim_(x→0) (((sin x)/x))^((sin x)/(x−sin x))

limx0(sinxx)sinxxsinx

Question Number 18614    Answers: 0   Comments: 1

Question Number 18607    Answers: 1   Comments: 1

A block of mass M is pulled vertically upward through a rope of mass m by applying force F on-one end of the rope. What force does the rope exert on the block?

AblockofmassMispulledverticallyupwardthrougharopeofmassmbyapplyingforceFononeendoftherope.Whatforcedoestheropeexertontheblock?

Question Number 18606    Answers: 0   Comments: 0

(1/3)+(3/(3×7))+(5/(3×7×11))+(7/(3×7×11×15))+...n terms

13+33×7+53×7×11+73×7×11×15+...nterms

Question Number 18604    Answers: 0   Comments: 0

Question Number 18603    Answers: 0   Comments: 0

The work function of a metal is 4 eV. If light of frequency 2.3 × 10^(15) Hz is incident on metal surface, then, (1) No photoelectron will be ejected (2) 2 photoelectron of zero kinetic energy are ejected (3) 1 photoelectron of zero kinetic energy is ejected (4) 1 photoelectron is ejected, which required the stopping potential of 5.52 volt

Theworkfunctionofametalis4eV.Iflightoffrequency2.3×1015Hzisincidentonmetalsurface,then,(1)Nophotoelectronwillbeejected(2)2photoelectronofzerokineticenergyareejected(3)1photoelectronofzerokineticenergyisejected(4)1photoelectronisejected,whichrequiredthestoppingpotentialof5.52volt

Question Number 18611    Answers: 1   Comments: 1

Without using L Hospital′s rule prove that lim_(x→0) ((sin x)/x)=1

WithoutusingLHospitalsruleprovethatlimx0sinxx=1

Question Number 18593    Answers: 1   Comments: 0

Question Number 18590    Answers: 1   Comments: 0

∫ ((sin x)/(1 + cos^2 x)) dx

sinx1+cos2xdx

Question Number 18588    Answers: 1   Comments: 0

sin x = ((2a + 3)/(a + 1)) How many a that can satisfy the equation above?

sinx=2a+3a+1Howmanyathatcansatisfytheequationabove?

Question Number 18587    Answers: 0   Comments: 2

lim_(x→0) ((x . tan x)/(x sin x − cos x + 1))

limx0x.tanxxsinxcosx+1

Question Number 18584    Answers: 1   Comments: 0

Prove sin (((3π)/(10)))=((1+(√5))/4)

Provesin(3π10)=1+54

Question Number 18575    Answers: 1   Comments: 0

If ( ) represents the least integer function, then the value of (10) + (10 + (1/(20))) + (10 + (2/(20))) + ... + (10 + ((19)/(20))) is equal to (1) 219 (2) 200 (3) 220 (4) 221

If()representstheleastintegerfunction,thenthevalueof(10)+(10+120)+(10+220)+...+(10+1920)isequalto(1)219(2)200(3)220(4)221

Question Number 18574    Answers: 1   Comments: 0

The maximum value of f(x) = 2 − ∣x∣^2 − 2x is equal to (1) 6 (2) 4 (3) 5 (4) 3

Themaximumvalueoff(x)=2x22xisequalto(1)6(2)4(3)5(4)3

Question Number 18568    Answers: 0   Comments: 0

The energy required to dislodge electron from excited isolated H-atom, IE_1 = 13.6 eV is (1) = 13.6 eV (2) > 13.6 eV (3) < 13.6 eV and > 3.4 eV (4) ≤ 3.4 eV

TheenergyrequiredtodislodgeelectronfromexcitedisolatedHatom,IE1=13.6eVis(1)=13.6eV(2)>13.6eV(3)<13.6eVand>3.4eV(4)3.4eV

Question Number 18581    Answers: 1   Comments: 0

In moving a body of mass m up and down a rough incline plane of inclination θ, work done is (S is length of the planck, and μ is coefficient of friction).

Inmovingabodyofmassmupanddownaroughinclineplaneofinclinationθ,workdoneis(Sislengthoftheplanck,andμiscoefficientoffriction).

Question Number 18561    Answers: 0   Comments: 2

The acceleration of an object is given by a(t) = cos(nπ), and its velocity at time t = 0 is (1/(2π)). Find both the net and the total distance traveled in the first 1.5 seconds.

Theaccelerationofanobjectisgivenbya(t)=cos(nπ),anditsvelocityattimet=0is12π.Findboththenetandthetotaldistancetraveledinthefirst1.5seconds.

Question Number 18556    Answers: 1   Comments: 0

Question Number 18551    Answers: 1   Comments: 0

Question Number 18550    Answers: 1   Comments: 1

Question Number 18549    Answers: 0   Comments: 0

A particle of mass 1 gram executes an oscillatory motion on the concave surface of a spherical dish of radius 2 m, placed on a horizontal plane. If the motion of the particle starts from a point on the dish at the height of 1 cm from the horizontal plane and the coefficient of friction is 0.01, how much total distance will be moved by the particle before it comes to rest?

Aparticleofmass1gramexecutesanoscillatorymotionontheconcavesurfaceofasphericaldishofradius2m,placedonahorizontalplane.Ifthemotionoftheparticlestartsfromapointonthedishattheheightof1cmfromthehorizontalplaneandthecoefficientoffrictionis0.01,howmuchtotaldistancewillbemovedbytheparticlebeforeitcomestorest?

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