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Question Number 18384    Answers: 1   Comments: 0

Let a, b, c ∈ R, a ≠ 0, such that a and 4a + 3b + 2c have the same sign. Show that the equation ax^2 + bx + c = 0 can not have both roots in the interval (1, 2).

Leta,b,cR,a0,suchthataand4a+3b+2chavethesamesign.Showthattheequationax2+bx+c=0cannothavebothrootsintheinterval(1,2).

Question Number 19200    Answers: 0   Comments: 5

A river of width d is flowing with speed u as shown in the figure. John can swim with maximum speed v relative to the river and can cross it in shortest time T. John starts at A. B is the point directly opposite to A on the other bank of the river. If t be the time John takes to reach the opposite bank, match the situation in the column I to the possibilities in column II. Column I (A) John reaches to the left of B (B) John reaches to the right of B (C) John reaches the point B (D) John drifts along the bank while minimizing the time Column II (p) t = T (q) t > T (r) u < v (s) u > v

Ariverofwidthdisflowingwithspeeduasshowninthefigure.JohncanswimwithmaximumspeedvrelativetotheriverandcancrossitinshortesttimeT.JohnstartsatA.BisthepointdirectlyoppositetoAontheotherbankoftheriver.IftbethetimeJohntakestoreachtheoppositebank,matchthesituationinthecolumnItothepossibilitiesincolumnII.ColumnI(A)JohnreachestotheleftofB(B)JohnreachestotherightofB(C)JohnreachesthepointB(D)JohndriftsalongthebankwhileminimizingthetimeColumnII(p)t=T(q)t>T(r)u<v(s)u>v

Question Number 18379    Answers: 1   Comments: 0

Question Number 18361    Answers: 0   Comments: 0

N propositions are judged by 2k−1 people. Each person assigns “true” to exactly M propositions and “false” to the other N−M (M ≤ N). To say a proposition is “approved” means it is true according to at least k judges. Find the minimum and maximum numbers of approved propositions given N, M and k.

Npropositionsarejudgedby2k1people.EachpersonassignstruetoexactlyMpropositionsandfalsetotheotherNM(MN).Tosayapropositionisapprovedmeansitistrueaccordingtoatleastkjudges.FindtheminimumandmaximumnumbersofapprovedpropositionsgivenN,Mandk.

Question Number 18377    Answers: 0   Comments: 0

Suppose one is given two vector field A and B in region of space such that, A(x,y,z) = 4xi + zj + y^2 z^2 k B(x,y,z) = yi +3j − yzk Find: C(x,y,z) if C = A ∧ B Also prove that, C(x,y,z) is perpendicular to A(x,y,z)

SupposeoneisgiventwovectorfieldAandBinregionofspacesuchthat,A(x,y,z)=4xi+zj+y2z2kB(x,y,z)=yi+3jyzkFind:C(x,y,z)ifC=ABAlsoprovethat,C(x,y,z)isperpendiculartoA(x,y,z)

Question Number 18721    Answers: 1   Comments: 0

Let ABC and ABC′ be two non- congruent triangles with sides AB = 4, AC = AC′ = 2(√2) and angle B = 30°. The absolute value of the difference between the areas of these triangles is

LetABCandABCbetwononcongruenttriangleswithsidesAB=4,AC=AC=22andangleB=30°.Theabsolutevalueofthedifferencebetweentheareasofthesetrianglesis

Question Number 18357    Answers: 0   Comments: 0

From the topic transformer prove that: e = (√2) ε cos(ωt)

Fromthetopictransformerprovethat:e=2εcos(ωt)

Question Number 18355    Answers: 0   Comments: 0

Question Number 18349    Answers: 0   Comments: 0

Consider the iteration x_(k+1) =x_k −(([f(x)]^2 )/(f(x_k +f(x_k ))−f(x_k ))), k=0,1,2,... for the solution of f(x)=0. Explain the connection with Newton′s method, and show that (x_k ) converges quadratically if x_0 is sufficiently close to the solution.

Considertheiterationxk+1=xk[f(x)]2f(xk+f(xk))f(xk),k=0,1,2,...forthesolutionoff(x)=0.ExplaintheconnectionwithNewtonsmethod,andshowthat(xk)convergesquadraticallyifx0issufficientlyclosetothesolution.

Question Number 18342    Answers: 2   Comments: 0

Question Number 19199    Answers: 1   Comments: 0

y=tan x^(tan x^(tan x) )

y=tanxtanxtanx

Question Number 18369    Answers: 1   Comments: 0

Prove that a^4 + b^4 + c^4 ≥ abc(a + b + c)

Provethata4+b4+c4abc(a+b+c)

Question Number 18366    Answers: 1   Comments: 0

Question Number 18365    Answers: 1   Comments: 0

Question Number 18364    Answers: 0   Comments: 0

Question Number 18363    Answers: 0   Comments: 0

Question Number 18362    Answers: 0   Comments: 0

Question Number 18333    Answers: 0   Comments: 1

Question Number 18469    Answers: 1   Comments: 0

Find Z_x and Z_y for each of the functions below (a) Z = 8x^2 y + 14xy^2 + 5y^2 x^3 (b) Z = 4x^3 y^2 + 2x^2 y^3 − 7xy^5

FindZxandZyforeachofthefunctionsbelow(a)Z=8x2y+14xy2+5y2x3(b)Z=4x3y2+2x2y37xy5

Question Number 18327    Answers: 1   Comments: 1

Question Number 18323    Answers: 0   Comments: 0

Σ((cos 2rθ)/(sin^2 2rθ−sin^2 θ))

Σcos2rθsin22rθsin2θ

Question Number 18322    Answers: 1   Comments: 1

The pulley arrangements are identical. The mass of the rope is negligible. In (a), the mass m is lifted up by attaching a mass (2m) to the other end of the rope. In (b), m is lifted up by pulling the other end of the rope with a constant downward force F = 2mg. In which case, the acceleration of m is more?

Thepulleyarrangementsareidentical.Themassoftheropeisnegligible.In(a),themassmisliftedupbyattachingamass(2m)totheotherendoftherope.In(b),misliftedupbypullingtheotherendoftheropewithaconstantdownwardforceF=2mg.Inwhichcase,theaccelerationofmismore?

Question Number 18318    Answers: 0   Comments: 3

∫ ((x + sinx)/(cosx)) dx

x+sinxcosxdx

Question Number 18307    Answers: 1   Comments: 0

Question Number 18306    Answers: 1   Comments: 0

Question Number 18320    Answers: 1   Comments: 0

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4 sin^2 (A/2) . If a, b and c denote the lengths of the sides of the triangle opposite to the angles A, B and C respectively, then (1) b + c = 4a (2) b + c = 2a (3) Locus of point A is an ellipse (4) Locus of point A is a pair of straight lines

InatriangleABCwithfixedbaseBC,thevertexAmovessuchthatcosB+cosC=4sin2A2.Ifa,bandcdenotethelengthsofthesidesofthetriangleoppositetotheanglesA,BandCrespectively,then(1)b+c=4a(2)b+c=2a(3)LocusofpointAisanellipse(4)LocusofpointAisapairofstraightlines

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