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We know that R=Q∪Q^− ⊂ C. Is there another set V such that C⊂V ? |
pH = pK_a + lg(C_b /C_a ) |
pH = (1/2) (14 − pK_b + pK_a ) |
pH = 14 − (1/2) ( pK_b − lgC_b ) |
Solve for n n^2 ≥n^3 −1 |
express the following in form of log a(f(x)) (i) 4log_a x−log_a (x^2 +x^3 ) (ii) log_a x + log_a (x+3) |
given that log 2=0.3.show that log 5=0.7 |
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if x=((a(1−r^n ))/(1−r)) make r the subject of the formula |
if x=((a(1−r^n ))/(1−r)) make r the subject of the formula |
∫_0 ^∞ {{ |
solve for M: c=Mln (z)+q |
Differentiate from the first principle: y = tan2x |
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Solve simultaneously xy + x + y = 23 ....... (i) xz + x + z = 41 ........ (ii) yz + y + z = 27 ........ (iii) |
find the determinant of the matrix below determinant ((0,4,0,0,0),(0,0,0,2,0),(0,0,3,0,0),(0,0,0,0,1),(5,0,0,0,0)) |
find the determinant of the matrix below determinant ((0,0,0,0,1),(0,0,0,2,0),(0,0,3,0,0),(0,4,0,0,0),(5,0,0,0,0)) |
find the determinant of the matrix below [(1,4,(−3),1),(2,0,6,3),(4,(−1),2,5),(1,0,(−2),4) ] |
evalute the value of Σ_(m=2 ) ^5 m^4 |
represent in sigma notation −1+4−9+16.................. |
About the Euler-Mascheroni Constant: γ = ∫_0 ^1 (1/(1 − x)) + (1/(ln x)) dx We can see that 1− x ≠ 0 ⇔ 1 ≠ x ; x = 0 → ln x ∄ . If x ≠ 0 and x ≠ 1, in the Cartesian Plane, this function has singularity x=0 and x=1. So, I could write f(x) = (1/(1 − x)) + (1/(ln x)) ∫_0 ^1 f(x) dx = lim_(A→0^+ ) lim_(B→1^− ) ∫_A ^B f(x) dx ? PS: Sorry by my worse English |
e^t = t |
Find the determinant of the matrix below. determinant (((3 1 5 3)),((4 3 8 5)),((6 2 1 7)),((8 5 8 1))) |
2+x=3 |
Pg 1925 Pg 1926 Pg 1927 Pg 1928 Pg 1929 Pg 1930 Pg 1931 Pg 1932 Pg 1933 Pg 1934 |