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Question Number 194279 Answers: 1 Comments: 0

$\underset{⏟}{}$

Question Number 194278 Answers: 0 Comments: 0

Question Number 194270 Answers: 1 Comments: 1

Question Number 194257 Answers: 1 Comments: 2

Know x,y,z ∈ R^+ such that: 2x + 4y + 7z = 2xyz Find Min(x+y+z)¿

$K n o w x, y, z \in R^{+} s u c h t h a t :$ $2 x + 4 y + 7 z = 2 x y z$ $F i n d M i n (x + y + z) ¿$

Question Number 194256 Answers: 2 Comments: 0

lim_(x→0) ((((1+tan x)/(1−tan x)) −1)/x) =?

$\lim_{x \to 0} \frac{\frac{1 + \tan x}{1 - \tan x} - 1}{x} = ?$

Question Number 194255 Answers: 0 Comments: 0

Find value m so that the function y=∣x^2 −2mx∣−6x covariaties on the interval (1;4)

$F i n d v a l u e m s o t h a t t h e f u n c t i o n$ $y =∣ x^{2} - 2 m x ∣ - 6 x c o v a r i a t i e s$ $o n t h e i n t e r v a l (1; 4)$

Question Number 194252 Answers: 2 Comments: 0

Find V = tan 9°−tan 27°−tan 63°+tan 81°

$Find V = \tan 9 ° - \tan 27 ° - \tan 63 ° + \tan 81 °$

Question Number 194250 Answers: 2 Comments: 0

find the value of a for which the limit lim_(x→0) ((sin (ax)−tan^(−1) (x)−x)/(x^3 +x^4 )) is finite and then evaluate the limit

$find the value of a for which the limit$ $\lim_{x \to 0} \frac{\sin (ax) - \tan^{- 1} (x) - x}{x^{3} + x^{4}} is finite$ $and then evaluate the limit$

Question Number 194248 Answers: 0 Comments: 0

Gyanashram classes weekly test by−Bittu sir CHEMISTRY TEST Electrochemistry 1. 2. 3. 4. 5. 6. ? 7. 8. 9. 10. ? 5 1. ? 2. objective 1. 1f 2. 127 g cu 3 4. ? 5.

$G y a n a s h r a m c l a s s e s$ $w e e k l y t e s t b y - B i t t u s i r$ $CHEMISTRY TEST$ $E l e c t r o c h e m i s t r y$ $1 .$ $2 .$ $3 .$ $4 .$ $5 .$ $6 . ?$ $7 .$ $8 .$ $9 .$ $10 . ?$ $5$ $1 . ?$ $2 .$ $o b j e c t ive$ $1 . 1 f$ $2 . 127 g c u$ $3$ $4 . ?$ $5 .$

Question Number 194241 Answers: 1 Comments: 0

Question Number 194240 Answers: 2 Comments: 0

Question Number 194238 Answers: 1 Comments: 0

Question Number 194237 Answers: 0 Comments: 1

how to evaluate 𝚺_(n=0) ^∞ (((−1)^n )/(k^n n!(zn+1)))

$how to evaluate$ $\underset{n = 0}{\sum^{\infty}} \frac{{(- 1)}^{n}}{k^{n} n! (z n + 1)}$

Question Number 194236 Answers: 1 Comments: 0

Question Number 194226 Answers: 3 Comments: 0

If x^2 − 65x = 64(√x) then (√(x − (√x) )) = ?

$If x^{2} - 65 x = 64 \sqrt{x} then \sqrt{x - \sqrt{x}} = ?$

Question Number 194219 Answers: 1 Comments: 0

Question Number 194218 Answers: 1 Comments: 2

Question Number 194216 Answers: 1 Comments: 0

Question Number 194211 Answers: 1 Comments: 0

(1/x^2 ) +(1/y^2 ) = (1/3) (d^2 y/dx^2 ) =?

$\frac{1}{x^{2}} + \frac{1}{y^{2}} = \frac{1}{3}$ $\frac{d^{2} y}{{dx}^{2}} = ?$

Question Number 194208 Answers: 0 Comments: 0

Question Number 194209 Answers: 0 Comments: 0

((1+kx))^(1/3) +x = 1 has two real roots . ⇒ k=? kx+1= 1−3x+3x^2 −x^( 3) x^( 3) −3x^( 2) + (k+3)x=0 x=0 x^( 2) −3x +k+3=0 1: Δ=0 9 − 4k −12=0 k= ((−3)/4) 2: k=−3 ⇒ x=0 is a root of x^( 2) −3x+k+3=0 ∴ k= ((−3)/4) or k=−3

$\sqrt[3]{1 + k x} + x = 1 h a s$ $t w o r e a l r o o t s . \Rightarrow k = ?$ $k x + 1 = 1 - 3 x + 3 x^{2} - x^{3}$ $x^{3} - 3 x^{2} + (k + 3) x = 0$ $x = 0$ $x^{2} - 3 x + k + 3 = 0$ $1 : Δ = 0$ $9 - 4 k - 12 = 0$ $k = \frac{- 3}{4}$ $2 : k = - 3 \Rightarrow x = 0 i s a r o o t o f$ $x^{2} - 3 x + k + 3 = 0$ $∴ k = \frac{- 3}{4} o r k = - 3$

Question Number 194207 Answers: 0 Comments: 0

Solve for x x^(x−4) =(√(3 ))

$Solve for x$ $x^{x - 4} = \sqrt{3}$

Question Number 194206 Answers: 1 Comments: 0

Question Number 194204 Answers: 1 Comments: 0

Question Number 194201 Answers: 1 Comments: 3

Question Number 194197 Answers: 1 Comments: 0

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