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Question Number 183527 Answers: 1 Comments: 2

Question Number 183524 Answers: 1 Comments: 0

Question Number 183521 Answers: 0 Comments: 0

When a bipolar transistor is turned on according to a scheme with a common base, the current gain coefficient is α=0.975. What will be the current gain of a bipolar transistor if it is turned on according to a scheme with a common emitter? a. 18.5 b. 81 c. 25 d. 39

$W h e n a b i p o l a r t r a n s i s t o r i s t u r n e d o n$ $a c c o r d i n g t o a s c h e m e w i t h a c o m m o n b a s e,$ $t h e c u r r e n t g a i n c o e f f i c i e n t i s α = 0.975 .$ $W h a t w i l l b e t h e c u r r e n t g a i n o f a b i p o l a r$ $t r a n s i s t o r i f i t i s t u r n e d o n a c c o r d i n g t o$ $a s c h e m e w i t h a c o m m o n e m i t t e r ?$ $a . 18.5$ $b . 81$ $c . 25$ $d . 39$

Question Number 183507 Answers: 0 Comments: 1

Question Number 183500 Answers: 1 Comments: 0

Question Number 183485 Answers: 2 Comments: 1

L=lim_(x→0) ((2sin x −2tan x +x^3 )/(6x−2sin 3x −9x^3 )) L= ((lim_(x→0) ((2sin x −2tan x +x^3 )/x^5 ))/(lim_(x→0) ((6x−2sin 3x −9x^3 )/x^5 ))) = (L_1 /L_2 )

$L = \lim_{x \to 0} \frac{2 \sin x - 2 \tan x + x^{3}}{6 x - 2 \sin 3 x - 9 x^{3}}$ $L = \frac{\lim_{x \to 0} \frac{2 \sin x - 2 \tan x + x^{3}}{x^{5}}}{\lim_{x \to 0} \frac{6 x - 2 \sin 3 x - 9 x^{3}}{x^{5}}} = \frac{L_{1}}{L_{2}}$

Question Number 183484 Answers: 0 Comments: 0

determinant ((),())

$\begin{matrix} \end{matrix}$

Question Number 183483 Answers: 0 Comments: 0

lim_(x→0^+ ) ((1−cos (√x))/( (√(x−(√(x−(√(x−(√(x−...)))))))))) =?

$\lim_{x \to 0^{+}} \frac{1 - \cos \sqrt{x}}{\sqrt{x - \sqrt{x - \sqrt{x - \sqrt{x - . . .}}}}} = ?$

Question Number 183480 Answers: 1 Comments: 1

Question Number 183479 Answers: 0 Comments: 0

determinant (((x+2=)),())

$\begin{matrix} x + 2 = \end{matrix}$

Question Number 183478 Answers: 1 Comments: 4

To Administrator Tinku Tara Dear sirs! please have a look at Q183382 and other posts of CElcedricjunior sir. He disobeys rules of the forum and intentionally and maciliously posts his answers as “comment” to the questions just to place his answers before the answers of other people. besides he ignores all kind advises of other people who asked him and showed him to post answers as “answer”, not as “comment”.

$\underset{―}{T o A d m i n i s t r a t o r T i n k u T a r a}$ $D e a r s i r s!$ $p l e a s e h a v e a l o o k a t Q 183382 a n d$ $o t h e r p o s t s o f C E l c e d r i c j u n i o r s i r .$ $H e d i s o b e y s r u l e s o f t h e f o r u m a n d$ $i n t e n t i o n a l l y a n d m a c i l i o u s l y p o s t s$ $h i s a n s w e r s a s ‘ ‘ {c o m m e n t}^{″} t o t h e$ $q u e s t i o n s j u s t t o p l a c e h i s a n s w e r s$ $b e f o r e t h e a n s w e r s o f o t h e r p e o p l e .$ $b e s i d e s h e i g n o r e s a l l k i n d a d v i s e s$ $o f o t h e r p e o p l e w h o a s k e d h i m a n d$ $s h o w e d h i m t o p o s t a n s w e r s a s$ $‘ ‘ {a n s w e r}^{″}, n o t a s ‘ ‘ {c o m m e n t}^{″} .$

Question Number 183477 Answers: 0 Comments: 0

determinant (((P(x)=3x(4−x)=12x−3x2)),(),(),(),())

$\begin{matrix} P (x) = 3 x (4 - x) = 12 x - 3 x 2 \end{matrix}$

Question Number 183465 Answers: 1 Comments: 0

Find the least value of (1−2x)(1−x). M.m

$Find the least value of$ $(1 - 2 x) (1 - x) .$ $M . m$

Question Number 183464 Answers: 2 Comments: 0

Find the Maximum value of 3x(4−x) M.m

$Find the Maximum value of$ $3 x (4 - x)$ $M . m$

Question Number 183459 Answers: 2 Comments: 0

It is given f(x)=(1+x)^n , n∈N. Find f(0)+f^′ (0)+((f^(′′) (0))/(2!))+((f′′′(0))/(3!))+...+((f^((n)) (0))/(n!)) .

$I t i s g i v e n f (x) = {(1 + x)}^{n}, n \in N . F i n d$ $f (0) + f^{^{'}} (0) + \frac{f^{^{″}} (0)}{2!} + \frac{f^{‴} (0)}{3!} + . . . + \frac{f^{(n)} (0)}{n!} .$

Question Number 183457 Answers: 2 Comments: 0

He went to work by his car at speed 120 km/hr and back home the same way 90 km/hr, find the average speed for the entire distance traveled.

$H e w e n t t o w o r k b y h i s c a r a t s p e e d 120 k m / h r$ $a n d b a c k h o m e t h e s a m e w a y 90 k m / h r, f i n d t h e$ $a v e r a g e s p e e d f o r t h e e n t i r e d i s t a n c e t r a v e l e d .$

Question Number 183455 Answers: 0 Comments: 1

Question Number 183450 Answers: 2 Comments: 0

∫_0 ^x^2 f(2t^3 −t^2 −6)dt = ln x then f(106)=?

$\underset{0}{\int^{x^{2}}} f (2 t^{3} - t^{2} - 6) d t = \ln x$ $t h e n f (106) = ?$

Question Number 183447 Answers: 0 Comments: 0

{ ((y=sec^n θ−cos^n θ)),((x=sec θ−cos θ)) :} xy ′+(x^2 +y^2 )y′′ =?

${\begin{cases} y = \sec^{n} θ - \cos^{n} θ \\ x = \sec θ - \cos θ \end{cases}$ $x y^{'} + (x^{2} + y^{2}) y^{″} = ?$

Question Number 183440 Answers: 2 Comments: 0

x(t)=2sin(((πt)/3)) y(t)=−3cos(((πt)/3))+4 cm What is the velocity at t=1s

$x (t) = 2 s i n (\frac{π t}{3})$ $y (t) = - 3 c o s (\frac{π t}{3}) + 4 c m$ $W h a t i s t h e v e l o c i t y a t t = 1 s$

Question Number 183432 Answers: 0 Comments: 1

Question Number 183425 Answers: 0 Comments: 0

find the rank of the matrix A and B by following row operation: A= [(1,2,3,(−1)),((−2),(−1),(−3),(−1)),(1,0,1,( 1)),(0,1,1,(−1)) ] B= [(( 1),( 2),(−1),( 4)),(( 2),( 4),( 3),( 5)),((−1),(−2),( 6),(−7)) ]

$f i n d t h e r a n k o f t h e m a t r i x A a n d B b y$ $f o l l o w i n g r o w o p e r a t i o n :$ $A = [\begin{matrix} 1 & 2 & 3 & - 1 \\ - 2 & - 1 & - 3 & - 1 \\ 1 & 0 & 1 & 1 \\ 0 & 1 & 1 & - 1 \end{matrix}]$ $B = [\begin{matrix} 1 & 2 & - 1 & 4 \\ 2 & 4 & 3 & 5 \\ - 1 & - 2 & 6 & - 7 \end{matrix}]$

Question Number 183424 Answers: 0 Comments: 0

Among the natural numbers not greater than 22 , the probability that the modulus of the difference of any two of the 3 randomly selected numbers is greater than 5 is equal to which of the following? a)15/22 b)1/7 c)1/22 d)1

$Among the natural numbers not$ $greater than 22, the probability that$ $the modulus of the difference of any$ $two of the 3 randomly selected numbers$ $is greater than 5 is equal to which of$ $the following ?$ $a) 1 5 / 22 b) 1 / 7 c) 1 / 22 d) 1$

Question Number 183631 Answers: 1 Comments: 1

determiner r? AB=6 AE=5

$d e t e r m i n e r r ?$ $A B = 6 A E = 5$

Question Number 183633 Answers: 1 Comments: 1

Montrer que ((a/b))^2 =(c/d)+1

$M o n t r e r q u e$ ${(\frac{a}{b})}^{2} = \frac{c}{d} + 1$

Question Number 183420 Answers: 2 Comments: 0

prove that Σ_(x=0) ^∞ ((4^x . x)/(x!)) = 4 e^4

$p r o v e t h a t \underset{x = 0}{\sum^{\infty}} \frac{4^{x} . x}{x!} = 4 e^{4}$

Pg 317 Pg 318 Pg 319 Pg 320 Pg 321 Pg 322 Pg 323 Pg 324 Pg 325 Pg 326

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