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AllQuestion and Answers: Page 323

Question Number 183419 Answers: 0 Comments: 2

Question Number 183413 Answers: 0 Comments: 0

Question Number 183411 Answers: 0 Comments: 2

Question Number 183409 Answers: 0 Comments: 3

Question Number 183405 Answers: 0 Comments: 2

Question Number 183393 Answers: 3 Comments: 0

Question Number 183389 Answers: 2 Comments: 0

Question Number 183382 Answers: 2 Comments: 4

Question Number 183381 Answers: 1 Comments: 2

((3n^5 + 4n^4 − 7n^3 + 5n^2 − 5)/(n + 1)) There can be no residue: a)0 b)2 c)4 d)5 e)9

$\frac{{3 n}^{5} + {4 n}^{4} - {7 n}^{3} + {5 n}^{2} - 5}{n + 1}$ $There can be no residue :$ $a) 0 b) 2 c) 4 d) 5 e) 9$

Question Number 183380 Answers: 0 Comments: 1

a>0 , b>0 { (((x−1)^2 + (y−7)^2 = a^2 )),(((x−2)^2 + (y−3)^2 = b^2 )) :} Find: (a+b)_(min) = ?

$a > 0, b > 0$ ${\begin{cases} {(x - 1)}^{2} + {(y - 7)}^{2} = a^{2} \\ {(x - 2)}^{2} + {(y - 3)}^{2} = b^{2} \end{cases}$ $Find : {(a + b)}_{\min} = ?$

Question Number 183594 Answers: 1 Comments: 0

log _(0.5) (√(1+x)) + 3log _(0.25) (1−x)= log _(1/16) (1−x^2 )^2 +2

$\log_{0.5} \sqrt{1 + x} + 3 \log_{0.25} (1 - x) = \log_{1 / 16} {(1 - x^{2})}^{2} + 2$

Question Number 183592 Answers: 1 Comments: 0

{ (((√(x/y)) +(√(y/z)) +(√(z/x)) = 3)),(((√(y/x)) +(√(z/y)) +(√(x/z)) = 3)),(((√(xyz)) = 1)) :}

${\begin{cases} \sqrt{\frac{x}{y}} + \sqrt{\frac{y}{z}} + \sqrt{\frac{z}{x}} = 3 \\ \sqrt{\frac{y}{x}} + \sqrt{\frac{z}{y}} + \sqrt{\frac{x}{z}} = 3 \\ \sqrt{x y z} = 1 \end{cases}$

Question Number 183376 Answers: 2 Comments: 1

Question Number 183366 Answers: 0 Comments: 2

6 of the 23 given points in the plane lie on a circle. Let n be the number of circles passing through at least 3 of these points. What is the maximum number of n?

$6 of the 23 given points in the plane$ $lie on a circle . Let n be the number of$ $circles passing through at least 3 of$ $these points . What is the maximum$ $number of n ?$

Question Number 183363 Answers: 1 Comments: 0

Find: 2003∙2005^3 −2004∙2002^3

$Find :$ $2003 \cdot 2005^{3} - 2004 \cdot 2002^{3}$

Question Number 183426 Answers: 2 Comments: 3

surface de la partie bleu du graphe?

$s u r f a c e d e l a p a r t i e b l e u$ $d u g r a p h e ?$

Question Number 183354 Answers: 0 Comments: 2

Given three point.Find the for the plane through the point P(0,1,0) Q(3,1,4) R(−1,0,1)

$G i v e n t h r e e p o i n t . F i n d t h e$ $f o r t h e p l a n e t h r o u g h t h e p o i n t$ $P (0, 1, 0) Q (3, 1, 4) R (- 1, 0, 1)$

Question Number 183353 Answers: 1 Comments: 0

For the function f(x)= { ((x^2 −3 if x<4)),(((x^2 /(x+4)) if x≥4)) :} Find (i) lim_(x→−4) f(x) ii)lim_(x→+4) f(x)

$F o r t h e f u n c t i o n$ $f (x) = {\begin{cases} x^{2} - 3 i f x < 4 \\ \frac{x^{2}}{x + 4} i f x ⩾ 4 \end{cases}$ $F i n d (i) \lim_{x \to - 4} f (x) i i) \lim_{x \to + 4} f (x)$

Question Number 183352 Answers: 0 Comments: 0

For the function f(x)= { ((1−x^2 if x< 2)),((2x+1 if x≥2)) :} Find (i)lim_(x→^− 2) f(x) (ii) lim_(x→2^+ ) f(x)

$F o r t h e f u n c t i o n$ $f (x) = {\begin{cases} 1 - x^{2} i f x < 2 \\ 2 x + 1 i f x ⩾ 2 \end{cases}$ $F i n d$ $(i) \lim_{x \to^{-} 2} f (x) (i i) \lim_{x \to 2^{+}} f (x)$

Question Number 183350 Answers: 3 Comments: 2

Find (a)lim_(x→∞) ((3x+2)/(x^2 −x+1)) (b)lim_(x→∞) ((√(x^2 −1))/(2x+1)) (c)lim_(x→5) (((√(3x+1)) −4)/(x−5))

$F i n d$ $(a) \lim_{x \to \infty} \frac{3 x + 2}{x^{2} - x + 1}$ $(b) \lim_{x \to \infty} \frac{\sqrt{x^{2} - 1}}{2 x + 1}$ $(c) \lim_{x \to 5} \frac{\sqrt{3 x + 1} - 4}{x - 5}$

Question Number 183344 Answers: 2 Comments: 1

Question Number 183342 Answers: 3 Comments: 0

Find: 3 − (2/(3 − (2/(3 − (2/(...)))))) = ?

$Find : 3 - \frac{2}{3 - \frac{2}{3 - \frac{2}{. . .}}} = ?$

Question Number 183330 Answers: 0 Comments: 2

S = sinhx+sinh^2 x + sinh^3 x+...+sinh^n x=?

$S = s i n h x + {s i n h}^{2} x + {s i n h}^{3} x + . . . + {s i n h}^{n} x = ?$

Question Number 183326 Answers: 2 Comments: 1

Question Number 183325 Answers: 1 Comments: 1

Question Number 183324 Answers: 2 Comments: 1

Find the minimum distance between C_f , C_g ; C_f : y^2 = 4ax , C_g : x^2 + y^2 −24ay+ 128a^2 = 0

$F i n d t h e m i n i m u m d i s t a n c e b e t w e e n C_{f}, C_{g}$ $; C_{f} : y^{2} = 4 a x, C_{g} : x^{2} + y^{2} - 24 a y + 128 a^{2} = 0$

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