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AllQuestion and Answers: Page 324

Question Number 183241 Answers: 1 Comments: 0

Find the equation of the line which is tangent to the parabola y^2 =12x and forms an angle of 45° with the line y=3x−4.

$F i n d t h e e q u a t i o n o f t h e l i n e w h i c h$ $i s t a n g e n t t o t h e p a r a b o l a y^{2} = 12 x$ $a n d f o r m s a n a n g l e o f 45 ° w i t h$ $t h e l i n e y = 3 x - 4 .$

Question Number 183240 Answers: 1 Comments: 0

find the value of cofficent μ in the following system from the determinat: 2x_1 +μx_2 +x_3 =0 (μ−1)x_1 −x_2 +2x_3 =0 4x_1 +x^2 +4x^3 =0

$f i n d t h e v a l u e o f c o f f i c e n t μ i n t h e f o l l o w i n g$ $s y s t e m f r o m t h e d e t e r m i n a t :$ $2 x_{1} + μ x_{2} + x_{3} = 0$ $(μ - 1) x_{1} - x_{2} + 2 x_{3} = 0$ $4 x_{1} + x^{2} + 4 x^{3} = 0$

Question Number 183239 Answers: 0 Comments: 0

determine eigenvalues and digonalize by row operation [(4,(−9),6,(12)),(9,(−1),4,6),(2,(−11),8,(16)),((−1),( 3),0,(−1)) ]

$d e t e r m i n e e i g e n v a l u e s a n d d i g o n a l i z e$ $b y r o w o p e r a t i o n$ $[\begin{matrix} 4 & - 9 & 6 & 12 \\ 9 & - 1 & 4 & 6 \\ 2 & - 11 & 8 & 16 \\ - 1 & 3 & 0 & - 1 \end{matrix}]$

Question Number 183236 Answers: 1 Comments: 2

dererminer la valeur x?

$d e r e r m i n e r l a v a l e u r x ?$

Question Number 183227 Answers: 4 Comments: 1

Question Number 183216 Answers: 1 Comments: 2

Question Number 183211 Answers: 1 Comments: 0

y^((iv)) +16y^((iii)) +9y^((ii)) +256y^((i)) +256y=0 M.m

$y^{(iv)} + {16 y}^{(iii)} + {9 y}^{(ii)} + {256 y}^{(i)} + 256 y = 0$ $M . m$

Question Number 183210 Answers: 1 Comments: 0

(d^3 y/dx^3 )+4(d^2 y/dx^2 )+(dy/dx)−6y=0 M.m

$\frac{d^{3} y}{{dx}^{3}} + 4 \frac{d^{2} y}{{dx}^{2}} + \frac{dy}{dx} - 6 y = 0$ $M . m$

Question Number 183209 Answers: 1 Comments: 0

Solve the Differential equation below (d^3 y/dx^3 )+8(d^2 y/dx^2 )+12(dy/dx)=0 M.m

$Solve the Differential equation below$ $\frac{d^{3} y}{{dx}^{3}} + 8 \frac{d^{2} y}{{dx}^{2}} + 12 \frac{dy}{dx} = 0$ $M . m$

Question Number 183205 Answers: 2 Comments: 0

Find the coefficient of x^(11) in (2x^2 +x−3)^6 .

$F i n d t h e c o e f f i c i e n t o f x^{11} i n$ ${(2 x^{2} + x - 3)}^{6} .$

Question Number 183202 Answers: 2 Comments: 0

ax^3 +bx^2 +c=0 x_1 = x_2 = x_3 =

${a x}^{3} + {b x}^{2} + c = 0$ $x_{1} =$ $x_{2} =$ $x_{3} =$

Question Number 183295 Answers: 2 Comments: 1

Question Number 183185 Answers: 1 Comments: 0

Question Number 183181 Answers: 2 Comments: 1

prove that (0/0)=1

$p r o v e t h a t \frac{0}{0} = 1$

Question Number 183174 Answers: 0 Comments: 2

In the given figure E is the mid point of AB. IF the area of ΔEBF is 8cm^2 .find the area of the parallelogram ABCD.

$In the given figure E is the mid point of AB .$ $IF the area of Δ EBF is {8 cm}^{2} . find the area of the parallelogram ABCD .$

Question Number 183165 Answers: 1 Comments: 0

Question Number 183167 Answers: 0 Comments: 2

In △ABC the following relationship holds: (m_b /b) + (m_c /c) ≤ (a/(2r)) ≤ (n_b /h_b ) + (n_c /h_c )

$In △ ABC the following relationship$ $holds :$ $\frac{m_{b}}{b} + \frac{m_{c}}{c} ⩽ \frac{a}{2 r} ⩽ \frac{n_{b}}{h_{b}} + \frac{n_{c}}{h_{c}}$

Question Number 183162 Answers: 1 Comments: 0

Question Number 183158 Answers: 1 Comments: 0

Given f(x)= (([(1/3)x]∣2x∣+Ax)/(∣4−x^2 ∣)) if f ′(−1)= 5 then A=? [ ] = floor function

$G i v e n f (x) = \frac{[\frac{1}{3} x] ∣ 2 x ∣ + A x}{∣ 4 - x^{2} ∣}$ $i f f^{'} (- 1) = 5 t h e n A = ?$ $[] = f l o o r f u n c t i o n$

Question Number 183157 Answers: 1 Comments: 0

∫ (dx/( ((x^3 +2019))^(1/3) )) =?

$\int \frac{d x}{\sqrt[3]{x^{3} + 2019}} = ?$

Question Number 183156 Answers: 1 Comments: 0

∫ ((sin 2x dx)/(sin x−sin^2 2x)) =?

$\int \frac{\sin 2 x d x}{\sin x - \sin^{2} 2 x} = ?$

Question Number 183136 Answers: 3 Comments: 0

lim_(x→0) ((sinx−x)/x^3 )=?

$\lim_{x \to 0} \frac{s i n x - x}{x^{3}} = ?$

Question Number 183124 Answers: 1 Comments: 0

Question Number 183123 Answers: 1 Comments: 0

∫ln(tanx)dx

$\int l n (t a n x) d x$

Question Number 183184 Answers: 1 Comments: 1

Question Number 183120 Answers: 2 Comments: 0

I−Incenter in △ABC A(2,2) , B(6,4) , C(4,8) , M(8,6) Find: MI = ?

$I - Incenter in △ ABC$ $A (2, 2), B (6, 4), C (4, 8), M (8, 6)$ $Find : MI = ?$

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