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Question Number 158288    Answers: 1   Comments: 0

Question Number 158287    Answers: 0   Comments: 0

Question Number 158281    Answers: 0   Comments: 2

Question Number 158276    Answers: 0   Comments: 0

if x;y;z≥0 then: 2 Σ_(cyc) x^2 (x^2 + y^2 ) ≥ Σ_(cyc) x(x^3 + z^3 ) + xyz(x+y+z)

ifx;y;z0then:2cycx2(x2+y2)cycx(x3+z3)+xyz(x+y+z)

Question Number 158275    Answers: 2   Comments: 0

Solve for real numbers: x^(32) + x^(16) + y^2 = 2 (√2) x^(12) y

Solveforrealnumbers:x32+x16+y2=22x12y

Question Number 158273    Answers: 0   Comments: 0

Question Number 158272    Answers: 1   Comments: 0

Question Number 158271    Answers: 0   Comments: 0

Question Number 158270    Answers: 0   Comments: 0

82,1336,18670,240004,2933338,34666672,400000006,? is there a valid pattern for these numbers?

82,1336,18670,240004,2933338,34666672,400000006,?isthereavalidpatternforthesenumbers?

Question Number 158267    Answers: 0   Comments: 0

soit:F={(x,y,z)∈R^3 /x−y−2z} et G=Vect(0,1,1) determiner l′intersection de F et G

soit:F={(x,y,z)R3/xy2z}etG=Vect(0,1,1)determinerlintersectiondeFetG

Question Number 158259    Answers: 1   Comments: 1

Given x,y∈R^+ and ((x/5)+(y/3))((5/x)+(3/y))=139. If maximum and minimum of ((x+y)/( (√(xy)) )) is M and n respectively, then what the value of 3M−4n.

Givenx,yR+and(x5+y3)(5x+3y)=139.Ifmaximumandminimumofx+yxyisMandnrespectively,thenwhatthevalueof3M4n.

Question Number 158252    Answers: 0   Comments: 0

Question Number 158625    Answers: 0   Comments: 1

EI(∂^4 y/∂x^4 )+ρS(∂^2 y/∂t^2 )=0 (1) y(x,0)=U_0 (x) (∂y/∂t)(x,0)=V_0 (x) ; EI(∂^2 y/∂x^2 )(0,t)=EI(∂^2 y/∂x^2 )(L,t)=0

EI4yx4+ρS2yt2=0(1)y(x,0)=U0(x)yt(x,0)=V0(x);EI2yx2(0,t)=EI2yx2(L,t)=0

Question Number 158245    Answers: 1   Comments: 0

Prove that: (((x-1)^2 )/x) + ((x+1)/( (√(x^2 +1)))) ≥ (√2) ; ∀x>0

Provethat:(x1)2x+x+1x2+12;x>0

Question Number 158241    Answers: 0   Comments: 0

Prove that: (((x-1)^2 )/x) + ((x+1)/( (√(x^2 +1)))) ≥ 2 ; ∀x>0

Provethat:(x1)2x+x+1x2+12;x>0

Question Number 158240    Answers: 1   Comments: 0

Prove that 5 divide n(4n^2 + 1)(6n^2 + 1) for any natural number n

Provethat5dividen(4n2+1)(6n2+1)foranynaturalnumbern

Question Number 158274    Answers: 1   Comments: 0

Solve for complex numbers: x^4 + (1 + i)x^3 + 2ix^2 + (i - 1)x - 1 = 0

Solveforcomplexnumbers:x4+(1+i)x3+2ix2+(i1)x1=0

Question Number 158230    Answers: 0   Comments: 0

∫(1/(1+ln x))dx=?

11+lnxdx=?

Question Number 158237    Answers: 0   Comments: 1

Question Number 158220    Answers: 0   Comments: 0

source: myself x^5 +3cx^2 −x−5c=0

source:myselfx5+3cx2x5c=0

Question Number 158228    Answers: 1   Comments: 0

∫((5x^3 −3x^2 +7x−3)/((x^2 +1)^2 ))dx Solve by first finding the partial fraction

5x33x2+7x3(x2+1)2dxSolvebyfirstfindingthepartialfraction

Question Number 158209    Answers: 1   Comments: 0

Question Number 158207    Answers: 1   Comments: 0

Question Number 158205    Answers: 0   Comments: 0

(1) lim_(x→0) (((e^x −1)sin x+tan^3 x)/(arctan x ln (1+4x)+4arcsin^4 x)) (2) lim_(x→0) ((1−cos x+ln (1+tan^2 2x)+2arcsin^3 x)/(1−cos 4x+sin^2 x))

(1)limx0(ex1)sinx+tan3xarctanxln(1+4x)+4arcsin4x(2)limx01cosx+ln(1+tan22x)+2arcsin3x1cos4x+sin2x

Question Number 158204    Answers: 2   Comments: 0

lim_(x→∞) (sin (√(x+1))−sin (√(x ))) =?

limx(sinx+1sinx)=?

Question Number 158203    Answers: 0   Comments: 0

lim_(n→∞) Σ_(k=1) ^n (1/n).e^((2k+1)/k) =?

limnnk=11n.e2k+1k=?

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