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AllQuestion and Answers: Page 83

Question Number 209263 Answers: 0 Comments: 5

6 different letters were written to 6 different people and 6 different envelopes were prepared with the addresses of these people written on them. In how many different ways can you put a letter in each envelope without putting a letter written to this person in the envelope with the name of any person?

Question Number 210090 Answers: 0 Comments: 9

Question Number 209246 Answers: 1 Comments: 0

Find f(x)=∫^( x) _( 0) (dt/(t+e^(f(t)) ))

$Find f (x) = {\int_{0}}^{x} \frac{dt}{t + e^{f (t)}}$

Question Number 209241 Answers: 2 Comments: 0

Question Number 209240 Answers: 1 Comments: 0

If x + ((49)/(x + 48)) = − 34 find (2x + 83)^3 + (1/((2x + 83)^3 ))

$I f x + \frac{49}{x + 48} = - 34$ $f i n d {(2 x + 83)}^{3} + \frac{1}{{(2 x + 83)}^{3}}$

Question Number 209234 Answers: 2 Comments: 0

Arrange in descending order: (√5) − (√2), (√7) − (√5) , (√(13)) − (√(11)) , (√(19)) − (√(17))

$Arrange in descending order :$ $\sqrt{5} - \sqrt{2}, \sqrt{7} - \sqrt{5}, \sqrt{13} - \sqrt{11}, \sqrt{19} - \sqrt{17}$

Question Number 209232 Answers: 1 Comments: 0

u_0 = a, u_(n+1) = (√(u_n v_n )) v_0 = b ∈ ]0,1[ , v_(n+1) = (1/(2(u_n +v_n ))) • show that a≤u_n ≤u_(n+1) ≤v_n ≤v_(n+1) ≤b • show that v_n − u_n ≤ ((a+b)/2^n )

$u_{0} = a, u_{n + 1} = \sqrt{u_{n} v_{n}}$ $v_{0} = b \in] 0, 1 [, v_{n + 1} = \frac{1}{2 (u_{n} + v_{n})}$ $∙ s h o w t h a t a ⩽ u_{n} ⩽ u_{n + 1} ⩽ v_{n} ⩽ v_{n + 1} ⩽ b$ $∙ s h o w t h a t v_{n} - u_{n} ⩽ \frac{a + b}{2^{n}}$

Question Number 209229 Answers: 6 Comments: 2

Question Number 209228 Answers: 1 Comments: 0

Question Number 209223 Answers: 2 Comments: 0

Question Number 209221 Answers: 0 Comments: 0

Question Number 209220 Answers: 1 Comments: 0

Question Number 209211 Answers: 0 Comments: 1

Question Number 209206 Answers: 0 Comments: 2

2 YouTube channels I think you might find useful.

$2 YouTube channels I think you might$ $find useful .$

Question Number 209193 Answers: 0 Comments: 1

A pin 6cm high is placed in front of a diverging lens of focal length 15cm, Calculate the position of the image formed

Question Number 209187 Answers: 3 Comments: 0

:: α , β and γ are roots of the following equation . Find the value of ” F ” : Equation : x^( 3) −2x −1=0 F := α^( 5) + β^( 5) + γ^( 5)

$:: α, β a n d γ a r e r o o t s o f t h e$ $f o l l o w i n g e q u a t i o n . F i n d t h e$ $v a l u e o f^{″} F^{″} :$ $E q u a t i o n : x^{3} - 2 x - 1 = 0$ $F := α^{5} + β^{5} + γ^{5}$

Question Number 209185 Answers: 0 Comments: 0

Question Number 209217 Answers: 2 Comments: 0

calculate : I= ∫_(0 ) ^( ∞) (( tan^( −1) (x))/((1 + x^( 2) )^( 2) )) dx = ?

$c a l c u l a t e :$ $I = \int_{0}^{\infty} \frac{{t a n}^{- 1} (x)}{{(1 + x^{2})}^{2}} d x = ?$

Question Number 209167 Answers: 2 Comments: 0

please convert 2531_((5000) ) to base 5002. thanks.

$p l e a s e c o n v e r t 2531_{(5000)} t o b a s e 5002 . t h a n k s .$

Question Number 209166 Answers: 1 Comments: 0

Question Number 209162 Answers: 2 Comments: 0

Cyclic quadrilateral ABCD is inscribed in circle. Point S is intersection of diagonals AC and BD (S is not center of the circle). If AB=BC=6 and BS=4, what is length of BD?

Question Number 209161 Answers: 3 Comments: 2

Question Number 209137 Answers: 2 Comments: 0

Question Number 209131 Answers: 1 Comments: 0

prove : curve { ((x(t)=((a+r.cos(t))/(a^2 +r^2 +2ar.cos(t))))),((y(t)=((r.sin(t))/(a^2 +r^2 +2ar.cos(t))))) :} 0≤t≤2π is circle , find center & radius

$p r o v e :$ $c u r v e {\begin{cases} x (t) = \frac{a + r . c o s (t)}{a^{2} + r^{2} + 2 a r . c o s (t)} \\ y (t) = \frac{r . s i n (t)}{a^{2} + r^{2} + 2 a r . c o s (t)} \end{cases} 0 ⩽ t ⩽ 2 π$ $i s c i r c l e, f i n d c e n t e r & r a d i u s$

Question Number 209129 Answers: 1 Comments: 0

Question Number 209128 Answers: 2 Comments: 0

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